The two consecutive integers are 2 and 3
<em><u>Solution:</u></em>
Let x and x + 1 are the two consecutive integers
Let "x" be the smallest integer
Let "x + 1" be the larger integer
<em><u>Given that, sum of 2 consecutive integers is one less than 3 times the smaller integer</u></em>
Therefore,
sum of 2 consecutive integers = one less than 3 times the smaller integer
sum of 2 consecutive integers = 3 times the smaller integer - 1
x + x + 1 = 3(x) - 1
2x + 1 = 3x - 1
3x - 2x = 1 + 1
x = 2
Thus the smaller integer = x = 2
Larger integer = x + 1 = 2 + 1 = 3
Thus the two consecutive integers are 2 and 3
Answer: The product of 42 times 43 is 1,806
Step-by-step explanation:
42 and 43 are both factors, and factor x factor = product
42(factor) x 43(factor) = 1,806(product)
To check work, divide the product by one of the factors, and the result should be the other factor.
1,806(product) divided by 42(factor#1) = 43(factor#2)
-or-
1,806(product) divided by 43(factor#2) = 42(factor#1)
Answer:
y = 3x/2 + 23 1/2
Or
y = 3x/2 + 47/2
Step-by-step explanation:
Find the slope
y = 3/2x - 3/2
Equation of a line
y = mx + c
m = 3/2
using a point slope form equation
Substitute the point into the equation
( -9 , 10)
y - y1 = m( x - x1)
x1 = -9
y1 = 10
y - 10 = 3/2( x - (-9)
y - 10 = 3/2( x + 9)
Open the bracket
y - 10 = (3x + 27)/2
y = ( 3x + 27)/2 + 10
LCM = 2
y = ( 3x + 27 + 20)/2
y = ( 3x + 47)/2
Separate to get the value of slope and intercept
y = 3x/2 + 47/2
y = 3x/2 + 23 1/2
The equation of the line is
y = 3x/2 + 23 1/2
Answer:
9/70
Step-by-step explanation:
X-3/10 for x= 3/7
3/7-3/10
9/70
