What is true about any point on a coordinate plane with a positive

Can't really find the answer. Any help?

prisoha [69]

a) you need to convert one of the prices so both of them are in the same units and you can compare them.

im going to convert the Japanese Yen into Euros as the numbers will be smaller but you can also do it the other way.

£1 = 188 japanese yen

?? = 39856 japanese yen

divide 39856 by 188 to get £212

this means 39856 Japanese Yen is equal to £212

then convert this into euros.

£1 = €1.41

£212 = ???

calculate 212 × 1.41 which gives you €298.92

this means 39856 Japanese Yen is equal to €298.92

the phone in Spain costs €352.50

this shows that the phone in Spain is more expensive than the one in Japan.

therefore, the mobile phone in Japan is cheaper.

b) from Part A, we know that the phone in Japan is 39856 Japanese Yen, which is equal to £212.

so now we need to convert €352.50 into Pounds (£) to compare the prices.

£1 = €1.41

?? = €352.50

divide 352.50 by 1.41 to get £250.

this means the phone in Spain costs £250 as €352.50 is equal to £250.

now we know the phone in Japan is £212 (in pounds) whereas the phone in Spain is £250 (in pounds).

we need to calculate the difference by doing £250 - £212 which equals £38

therefore, the phone in Japan is cheaper than the phone in Spain by £38

7 0

3 years ago

In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien

diamong [38]

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = $\frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}$

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2 = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) = $\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)}$ = $\frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)}$ = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

4 0

3 years ago

A quadratic function y=f(x)y=f(x) is plotted on a graph and the vertex of the resulting parabola is (5, -6)(5,−6). What is the v

MariettaO [177]

Answer:

The vertex is at (5,4).

Step-by-step explanation:

I graphed both of the functions on the graph below.

If this answer is correct, please make me Brainliest!

5 0

2 years ago

Solve for x. Round to the nearest tenth, if necessary. S 9 х Q 75° R

ivann1987 [24]

Trigonometry:

Sine 75 = x/ 9
x = 9 Sine 75
x = 8.7

8 0

3 years ago

What is the square root of 9 2/5 cubed?

taurus [48]

Answer:

28.8

Step-by-step explanation:

7 0

2 years ago