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jeka57 [31]
3 years ago
15

What is true about any point on a coordinate plane with a positive

Mathematics
1 answer:
mafiozo [28]3 years ago
8 0
Your answer is gonna be A
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N-4-9<br> I really need help with this
yKpoI14uk [10]

Answer:

n - 13

Step-by-step explanation:

n-4-9

We can combine like terms.

n - (4+9)

n - 13

8 0
3 years ago
How can i simplify 16m cubed -10m squared
adoni [48]
16m cubed - 10m squared......
take out the common factors
they both have a two that can go into it and both have two m's you can take out
so then it becomes
2m squared(8m-5) and thats your answer (:
5 0
3 years ago
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A garden shed is 5 m from back to front; the back wall is 1.9 m high and the tool
krek1111 [17]

Answer:

yagni

Step-by-step explanation:

de bo dam me ha te cu te mala panga uh hu ayeee

7 0
3 years ago
Factor the polynomial function over the complex numbers. f(x)=x^4-x^3-2x−4 Enter your answer in the box. f(x) = The answer is: (
Vladimir79 [104]

Answer:

Factors: (x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0

Step-by-step explanation:

We are given a polynomial:

f(x)=x^4-x^3-2x-4

We have to factor the given polynomial into its complex factors.

The factorization can be done as follows:

f(x)=x^4-x^3-2x-4 = 0\\x^4-x^3-2x-4 = 0\\x^4-4-x^3-2x=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^4-4)-(x^3+2x) = 0\\(x^2+2)(x^2-2)-x(x^2+2) = 0\\(x^2+2)(x^2-2-x) = 0\\(x^2+2)(x^2-x-2) = 0\\(x^2+2)(x^2-2x-+x-2) = 0\\(x^2+2)((x(x-2)+1(x-2))=0\\(x^2+2)(x+1)(x-2)=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^2-(\sqrt{-2})^2)(x+1)(x-2)=0\\(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0

8 0
3 years ago
Solve the system of equations.<br> – 5x + 2y = 9<br> y = 7x<br><br> X =<br> Y =
Sphinxa [80]

Answer:

<em> x−y = 9 , x + y = 6</em>

<em>x + y = 4  ,  x − y = 2</em>

<em>x + 2 y = 4  ,  x − y = − 3 </em>

<em>try out these examples?</em>

<em />

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5 0
3 years ago
Read 2 more answers
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