All categories

3 years ago

Simplify 674\(6+9\3)

Mathematics

2 answers:

alina1380 [7]3 years ago

5 0

Here is the equation:

$647 \div (6+9 \div 3)$

Use PEMDAS

$Parentheses \\ Exponents \\ Multiplication \\ Division \\ Addition \\ Subtraction$

Parentheses is first.

$6+9\div3$

Division comes before addition.

$9 \div 3 = 3 \\ 6+3 = \bf 9$

Your new equation is:

$674 \div (9)$

Divide

$674 \div 9 = 74.89$

Your answer is 74.89

WARRIOR [948]3 years ago

3 0

Given: 674/(6+9/3)

Follow PEMDAS:

674/(6+3)

674/9

74.89 (I rounded the answer)

You might be interested in

Chuck built a garden in the shape of a rectangle in his backyard. The width of the garden is 7 feet and the length of the garden

Nastasia [14]

The answer is 25 because of the Pythagorean theorem. 49+576=625 625 squared=25

5 0

3 years ago

2. picking a number from 1 to 5 and choosing the color red, white, or blue

bekas [8.4K]

Answer:

i would choose a 3 and color red

Step-by-step explanation:

i still don't understand the question tho

7 0

3 years ago

Jose graphed the amount of money paid in relation to the number of avocados bought. Which stamens best describes the unit rate f

aev [14]

Answer:

$c \: 5dollar \: each$

6 0

3 years ago

Read 2 more answers

Y=4 (0.5)* exponential function y=2(5)* exponential function

Vlad1618 [11]

Yes you are correct that is the answer.

6 0

3 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0

2 years ago