Answer:
3.125
Step-by-step explanation:
Answer:

Step-by-step explanation:
When simplifying an exponent a way to do is to expand the exponent. This means that it will now be

Whenever you see an x or y on the numerator and denominator cross it out because it is the same thing as 1
When you cross out all of the x's and y's the only variable left is y in the denominator. This means that the answer is 
Answer:
A)2
Step-by-step explanation:
we would like to integrate the following definite Integral:

use constant integration rule which yields:

notice that we can rewrite √x using Law of exponent therefore we obtain:

once again use law of exponent which yields:

use exponent integration rule which yields;

simplify which yields:

recall fundamental theorem:

simplify:

hence
our answer is A
If you solve for the vertex of the function, you would get (-3, -1). So I think it would be x = -3 and the function’s maximum value would be -1. Hope this helps!! :)