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Firlakuza [10]
3 years ago
6

What’s the value of Y?

Mathematics
1 answer:
Montano1993 [528]3 years ago
7 0

Answer:

44

Step-by-step explanation:

if 88 is the right angle degree, that means the acute angle would be half of 88.

88÷2=44

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The mark up on an item is $3.75. If the mark up is 35%, what was the original price? Round
oksian1 [2.3K]

Answer:

$10.71

Step-by-step explanation:

\frac{3.75}{y} =\frac{35}{100}

y × 35 = 3.75 × 100

35y = 375

35y ÷ 35 = 375 ÷ 35

y=10\frac{5}{7}

y = 10.7142857143

10.7142857143 round to 10.71

5 0
3 years ago
Select the postulate that specifies the minimum number of points in space
Tanzania [10]
Postulate1:A line contains atleast 2 points.Postulate1a:A plane contains at least 3 points not all on one line.Postulate1b:Space contains atleast four points not all on one plane
6 0
3 years ago
Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5
Gennadij [26K]

Answer:

Points J and K could be located at:

J(2,2)

K(6,2)

Step-by-step explanation:

Consider the vertices have a x and y coordinate:

A: x coordinate=-7  y coordinate=-2

B: x coordinate=1  y coordinate=-2

C: x coordinate=1  y coordinate=-8

D: x coordinate=-7  y coordinate=-8

G: x coordinate=2  y coordinate=5

H: x coordinate=6  y coordinate=5

Then it is possible to calculate the distance between the x and y coordinates:

x coordinate of Vertices AB:

x coordinate of B- x coordinate of A=1-(-7)=8

The distance between A and B is 8

y coordinate of Vertices AC:

y coordinate of A- y coordinate of C=-2-(-8)=6

The distance between A and C is 6

Then we know that the side AB of Rectangle ABCD measures 8 and the side AC, measures 6.

Repeat the analysis  with Rectangle GHJK. In this case, is only possible to calculate the distance with x coordinate.

x coordinate of Vertices GH:

x coordinate of H- x coordinate of G=6-(2)=4

The distance between G and H is 4

We can see that the distance in x of the Rectangle ABCD is 8, and the distance in x of the Rectangle GHJK is 4, it means that <em>the measure of ABCD is twice GHJK.</em>

Then, if the distance in y coordinate of Vertices AC is 6, we could say that the distance in<em> y coordinate of Vertices GJ is 3.</em>

<em />

Points J and K could be located at:

J(2,2)

K(6,2)

3 0
3 years ago
PLEASE HELP I BEG OF YOU!???
k0ka [10]

Answer:

24.9

first to find the price of the DVD's you multiply 5 x 4.40 which is 22, then you add the 2.90 10 get 24.90.

btw plz put me as brainliest.

7 0
3 years ago
Find the area lying outside r=6cos(theta) and inside r=3+3cos(theta)
Sloan [31]
The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b... 

<span>the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. </span>
<span>2cosθ = 1 => θ = ±π/3 </span>

<span>A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ </span>
<span>= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ </span>
<span>= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. </span>
<span>.............where I have used ∫(cosθ)².dθ=1/4[2θ + sin(2θ)] </span>
<span>= 3θ/2 +sin(2θ) - sin(θ) </span>

<span>Area = A(π/3) - A(-π/3) </span>
<span>= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) </span>
<span>= π.</span>
7 0
4 years ago
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