Is there any other optional answers that go with this question
Answer:
x = 6
, y = 4
Step-by-step explanation:
Solve the following system:
{x + y = 10
x - y = 2
Hint: | Choose an equation and a variable to solve for.
In the first equation, look to solve for y:
{x + y = 10
x - y = 2
Hint: | Solve for y.
Subtract x from both sides:
{y = 10 - x
x - y = 2
Hint: | Perform a substitution.
Substitute y = 10 - x into the second equation:
{y = 10 - x
2 x - 10 = 2
Hint: | Choose an equation and a variable to solve for.
In the second equation, look to solve for x:
{y = 10 - x
2 x - 10 = 2
Hint: | Isolate terms with x to the left hand side.
Add 10 to both sides:
{y = 10 - x
2 x = 12
Hint: | Solve for x.
Divide both sides by 2:
{y = 10 - x
x = 6
Hint: | Perform a back substitution.
Substitute x = 6 into the first equation:
{y = 4
x = 6
Hint: | Sort results.
Collect results in alphabetical order:
Answer: {x = 6
, y = 4
Answer:
1) 0.1667
2) 0.8333
3) 1
Step-by-step explanation:
Let A be the event that 3 is observed on the first trial.
Let B be the event that at least two trials are required to observe a 3
a) A six-sided die has 6 possible outcomes of 1,2,3,4,5,6
3 is one of the six possible outcomes
P(A) = no of favourable outcomes /no of possible outcomes
P(A) = 1/6 = 0.1667
b) The event of requiring at least two trials to observe a 3 is the event of not observing a 3 on the first trial.
P(B) = P(A')
P(A')= 1 - P(A)
P(B) = 1 - 1/6
= 5/6 = 0.8333
c) P(AnB) = P(A) + P(B)
= 1/6 + 5/6
= 6/6 = 1
Answer:
5 Pull Ups 10 push ups and 15 squats+ if you want 10 jumping jacks.
Step-by-step explanation:
Uhh... what are the options?
Here's some possible ones:
0.2
1/5
