The table shows the cost to have various numbers of pizzas delivered from Papas Slice of Italy pizzeria. Is the relationship bet
ween the cost and the number of pizzas proportional? Explain.
2 answers:
Answer: No
Step-by-step explanation:
We know that the equation for direct proportion between two quantities x ( independent variable) and y (dependent variable) is given by :-
, where k is the proportionality constant.
if the relationship between the cost (dependent variable ) and the number of pizzas (independent variable ) is proportional, then k in the above equation remains constant for each row.
Let
1)
2)
But 10≠12.50, thus the value for k is not fixed.
Hence, the relationship between the cost and the number of pizzas is not proportional.
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Answer:
(a) 93.19%
(b) 267.3
Step-by-step explanation:
The population mean and standard deviation are given as 502 and 116 respectively.
Consider, <em>X</em> be the random variable that shows the SAT critical reading score is normally distributed.
(a) The percent of the SAT verbal scores are less than 675 can be calculated as:
Thus, the required percentage is 93.19%
(b)
The number of SAT verbal scores that are expected to be greater than 575 can be calculated as:
So,
Out of 1000 randomly selected SAT verbal scores, 1000(0.2673) = 267.3 are expected to have greater than 575.
Answer:
Step-by-step explanation:
Hello!
There are some values missing, so I'll find the probability distribution using others as example. Afterwards you can calculate the ones corresponding to this exercise following the same steps.
Considering there are 5000 undergraduates registered in the college.
465 are taking one course
658 are taking two courses
566 are taking three courses
1877 are taking four courses
1344 are taking five courses
90 are taking six courses
First you have to define the variable of interest. To identify it you have to ask yourself the following question: what is the characteristic of this population that is being measured?
The answer is "the number of courses an undergraduate is taking" and this will be the study variable X
X can take values from 1 to 6 courses.
To calculate the probability of each value of X, you have to divide the "number of students taking Xi courses" by "total number of students registered in the college"
For
X=1
P(1)= 465/5000= 0.093
X=2
P(2)= 658/5000= 0.1316
X=3
P(3)= 566/5000= 0.1132
X=4
P(4)= 1877/5000= 0.3754
X=5
P(5)= 1344/5000= 0.2688
X=6
P(6)= 90/5000= 0.018
For this to be a probability distribution the following condition should be met:
F(X)= ∑P(X) = 1
In this example: 0.093 + 0.1316 + 0.1132 + 0.3754 + 0.2688 + 0.018 = 1
I hope this helps!
