Answer;
-Malachite green
Explanation;
-Malachite green is also used in endospore staining, since it can directly stain endospores within bacterial cells; here a safranin counterstain is often used.
-Because of their tough protein coats made of keratin, spores are highly resistant to normal staining procedures. The primary stain in the endospore stain procedure, malachite green, is driven into the cells with heat.
Answer:
40 individuals
Explanation:
The homozygous recessive percentage is equal to q2.
Recessive genotype frequency, q 2 is 1/1000000 = 0.000001
therefore, q =
=
= 0.001 = allele "a" frequency
and p + q = 1, thus, p = 1 – q = 1 – 0.001 = 0.999
thus, the frequency of allele a = q = 0.001 and the frequency of allele A = p = 0.999
Carriers are heterozygous and are equal to 2pq.
So, 2pq = 2 x 0.999 x 0.001 x 20,000 = 39.96 (round of to 40)
Hence, 40 individuals will be expected to carry the recessive allele.
He never liked being on the hot seat and he'd found his niche<span> with this job.</span><span>
</span>
Explanation:
Such an offspring would have the genotype YY, which are the dominant alleles that code for yellow colour in bananas.
In the Punnett's Square, none of the offspring have YY genotype. Hence the answer is 0%.
I believe it is D) heliocentric !