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inn [45]
3 years ago
5

Using Pemdas what’s is the solution?

Mathematics
2 answers:
solniwko [45]3 years ago
4 0

2/3 - 5/6 (8-1/6) + 1/2

do the inside parenthesis

2/3 - 5/6 (7 5/6) + 1/2

change to an improper fraction ( 7 5/6 = (6*7+5)/6 =47/6)

2/3 - 5/6 * (47/6) + 1/2

2/3 - 5/6 * 47/6 + 1/2

2/3 - 235/ 36 + 1/2

get a common denominator of 36

2/3 *12/12 -235/36 + 1/2 *18/18

24/36 -235/36 + 18/36

(24-235+18)/36

-193/36

change to a mixed number

36 goes into 193 5 times with 13 left over

-5 13/36

EleoNora [17]3 years ago
3 0

Answer:

the answer is 13/36

Step-by-step explain

hope this helps :)

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noelle is drawing fraction bars to model the sum of 1/5 and 3/4. What is the smallest number of equally sized pieces each fracti
Bess [88]

Answer:

the smallest number of equally sized pieces is 20

Step-by-step explanation:

The computation of the smallest number of equally sized pieces is as follows:

Given that

The sum of 1 by 5 and 3/4

Now

if we sum it

= 1 ÷ 5 + 3 ÷ 4

= 4 + 15 ÷ 20

= 19 ÷ 20

Now as if we do the lcm so the denominator sum be 20

Therefore the smallest number of equally sized pieces is 20

6 0
3 years ago
Find the perimeter of a quarter circle that has a diameter of 7 feet.
MAXImum [283]

Answer:

21.99ft

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The sum of the first number cubed and the second number is 500 and the product is a maximum.
soldier1979 [14.2K]

We are given the following information:

the sum of the first number cubed and the second number is 500

their product is a maximum

We are looking for the 2 missing numbers.

To answer this, let's represent the two numbers as x and w.

From the given, we can form the following equation:

x^3+w=500

We can then express y as:

w=500-x^3

We can express their product as:

x(500-x^3)=500x-x^4

To find the maximum value of x, let's solve for the derivative of -x^4 + 500 x.

\begin{gathered} f(x)=-x^4+500x \\ f^{\prime}(x)=-4x^3+500 \end{gathered}

Then we solve for the value of x where f'(x) = 0.

\begin{gathered} -4x^3+500=0 \\ -4x^3=-500 \\ x^3=125 \\ x=5 \end{gathered}

Then we use x = 5 to solve for the second number, w.

\begin{gathered} w=500-x^3 \\ w=500-5^3 \\ w=500-125 \\ w=375 \end{gathered}

Therefore, the two numbers are 5 and 375.

3 0
1 year ago
The function h(t)=-4.87t^2+18.75t is used to model the height of an object projected in the air, where h(t) is the height in met
Feliz [49]

Answer:

Domain: t≥0

Range:h(t) ≤ 0.85

Step-by-step explanation:

The domain of a function is all the valid values you can enter into the function. Because time can't be negative the domain is t>0. The range or h(t) is the result, because the object can't go through the ground, it can't be less than zero. 0≤h(t)

0≤-4.87t^2+18.75t

0≤-4.87t+18.75

-18.75≤-4.87t

which is approx.: 0.85≥t or t≤0.85

4 0
3 years ago
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Answer:

Step-by-step explanation:

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