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bija089 [108]
3 years ago
9

If f(x) = x-5 and g(x) = 3x2-1, what is (fºg)(x)?

Mathematics
1 answer:
Kobotan [32]3 years ago
4 0

Answer:

<h2>(f\circ \: g)(x) =  {3x}^{2}  - 6</h2>

Step-by-step explanation:

f(x) = x - 5

g(x) = 3x² - 1

To find (fºg)(x) substitute g(x) into f(x) that's for every x in f (x) replace it with g (x)

That's

<h3>(f\circ \: g)(x) = 3 {x}^{2}  -1 - 5</h3>

We have the final answer as

<h3>(f\circ \: g)(x) =  {3x}^{2}  - 6</h3>

Hope this helps you

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A) 3 in

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<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Geometry</u>

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  • Diameter: d = 2r

Step-by-step explanation:

<u>Step 1: Define</u>

SA = 23 in²

<u>Step 2: Find </u><em><u>r</u></em>

  1. Substitute [SAS]:                    23 in² = 4πr²
  2. Isolate <em>r </em>term:                         23 in²/(4π) = r²
  3. Isolate <em>r</em>:                                  √[23 in²/(4π)] = r
  4. Rewrite:                                   r = √[23 in²/(4π)]
  5. Evaluate:                                 r = 1.35288 in

<u>Step 3: Find </u><em><u>d</u></em>

  1. Substitute [D]:                    d = 2(1.35288 in)
  2. Multiply:                              d = 2.70576 in
  3. Round:                                d ≈ 3 in
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Step-by-step explanation:


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Answer:

x=4

Step-by-step explanation:

3x + 6 = 18

3x = 18 - 6 = 12

x = 4

4 0
2 years ago
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