Answer:
The formula to enter in E14 is as follows:
=DAYS(D14,$E$10)
Explanation:
Required
Formula to calculate the number of days between E10 and D14
The syntax to do this is:
=DAYS(end_date,start_date)
So, we have:
=DAYS(D14,E10)
The question requires a mix of relative and mixed references because cell E10 will be constant in calculating the difference for dates in other cells.
In other words, the initial date is constant for all
So, the update formula is:
=DAYS(D14,$E$10)
Notice the $ between in E10; this represents mixed referencing
When dragged to E15 till E68, the formulas in the respective cells will be:
=DAYS(D15,$E$10) .............................. =DAYS(D68,$E$10)
B. Strategic thinking
<u>Explanation:</u>
Strategic thinking helps to come up with great ideas that makes the company better than the other company. One can apply strategic thinking to arrive at decisions that can be related to your work or personal life. Strategic thinking involves developing an entire set of critical skills. Strategic thinking enables a business owner to determine how to use these resources most effectively and advance the company toward its objectives. Strategic thinking focuses the management team on markets that are most likely to succeed.
Answer:
It can improve the quality of human life because it can be used as a learning and education media, the mass communication media in promoting and campaigning practical and important issues, such as the health and social area. It provides wider knowledge and can help in gaining and accessing information.
<em>That</em><em>'</em><em>s</em><em> </em><em>my</em><em> </em><em>answer</em>
Following are the program to calculate even digits sum:
<h3>Program:</h3>
#include <iostream>//header file
using namespace std;
int main()//main method
{
int a[10],s=0,i;//defining an array and an integer variable
cout<<"Enter array values: ";//print message
for(i=0;i<=9;i++)//defining a loop that input array value
{
cin>>a[i];//input array value
}
for(int i=0;i<=9;i++)//defining loop that check array value
{
if(a[i]%2==0)//defining if block that checks even number condition value
{
s=s+a[i];//adding even number value
}
}
cout<<"The sum of even number is: "<<s;//print even number sum value
return 0;
}
Program Explanation:
- Defining a header file.
- Defining the main method.
- Inside the main method, an integer array "a", and two integer variable "s,i" is declared.
- In the next step, a for loop is declared that input the array value, and after input value another loop is declared that check even number value in array.
- In this loop it adds array value and after adding the value a print method is declared that prints its value.
Output:
Please find the attached file.
Find out more information about the even number here:
brainly.com/question/4184435
