Opinions are always based on facts. a. True b. False
2 answers:
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Solution :
check_palindrome
lower__string
string
_lower()
Let stack = new Stack()
Let queue = new Queue();
for each character c in lower_case_string:
stack.push(c);
queue.enqueue(c);
let isPalindrome = true;
while queue is not empty {
if (queue.remove().equals(stack.pop())) {
continue;
} else {
isPalindrome=false;
break while loop;
}
}
return isPalindrome
Input = aabb
output = true
input =abcd
output = false
Answer:
Explanation:
The following code is written in Java. It creates the class OrthokonBoard which holds a 4x4 grid board in which each space is an "x" . Once the user creates an OrthokonBoard object they need to pass the positions of player 1 and 2 as an integer array of an x and y coordinate on the grid. Then the constructor of the object places the players on the board. A test version of the class was added to the main method and the output can be seen in the attached picture below.
class Brainly {
public static void main(String[] args) {
int[] player1Pos = {1, 1};
int[] player2Pos = {3,3};
OrthokonBoard newBoard = new OrthokonBoard(player1Pos, player2Pos);
for (char[] x : newBoard.board) {
System.out.println("");
for ( char y : x) {
System.out.print(y + " ");
}
}
}
}
class OrthokonBoard {
char[][] board = {{'x', 'x', 'x', 'x'}, {'x', 'x', 'x', 'x'}, {'x', 'x', 'x', 'x'}, {'x', 'x', 'x', 'x'}};
public OrthokonBoard(int[] playerOnePos, int[] playerTwoPos) {
board[playerOnePos[0]][playerOnePos[1]] = '1';
board[playerTwoPos[0]][playerTwoPos[1]] = '2';
}
}
