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koban [17]
3 years ago
13

PLEASE THIS IS 15 POINTS PLEASE

Mathematics
1 answer:
aniked [119]3 years ago
5 0

5)

Based on graph x > -3

Answer: x > - 3 (last one)

6)

m> - 2

So the answer is the last one.

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Look at the figure if tan x=3/y and cos x =y/z what is the value of sin x?
castortr0y [4]
Recall:

The tan of the measure of an angle is the ratio of the opposite side to the adjacent side to that angle, that is :

\displaystyle{ \tan x^{\circ}= \frac{opposite\ side}{adjacent \ side}. 

Since this ratio is 3/y, we denote the opposite side, and adjacent side respectively by 3 and y. 

(Technically we should write 3t and yt, but we try our luck as we see y in the second ratio too!)


Similarly, \displaystyle{\cos x^{\circ}= \frac{adjacent\ side}{hypothenuse}.


The adjacent side is already denoted by y, so we denote the length of the hypotenuse by z.



Now the sides of the right triangle are complete. 

\displaystyle{ \sin x^{\circ}= \frac{opposite\ side}{hypotenuse}= \frac{3}{z}


Answer: A

5 0
3 years ago
Read 2 more answers
Write a rule for the nth term of the geometric sequence if r = 1/4 and a3 = 2.
GarryVolchara [31]

Answer:

a_{n} = 32(\frac{1}{4})^{n-1}

Step-by-step explanation:

The nth term of a geometric sequence is given by the following equation.

a_{n+1} = ra_{n}

In which r is the common ratio.

This can be expanded for the nth term in the following way:

a_{n} = a_{1}r^{n-1}

In which a_{1} is the first term.

This means that for example:

a_{3} = a_{1}r^{3-1}

So

a_{3} = a_{1}r^{2}

2 = a_{1}(\frac{1}{4})^{2}

2 = \frac{a_{1}}{16}

a_{1} = 32

Then

a_{n} = 32(\frac{1}{4})^{n-1}

4 0
3 years ago
Find the equation of the line whose slope is -3 and which passes through the point (-5, 3)
nadezda [96]

Answer:

y=-3x-12

Step-by-step explanation:

Plug into equation y=mx+b

3=(-3)-5+b

Simplify

3=15+b

Subtract 15 from both sides

-12=b

Add slope and y-intercept into base equation

y=-3x-12

4 0
3 years ago
NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.​
slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

The bases of a triangular prism are the triangles.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2

<u>Total Surface Area</u>

Area of the isosceles triangle:

\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2

Total surface area:

\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2

<u>Total Surface Area</u>

Area of a pentagon:

\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2

where a is the side length.

Therefore:

\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)

Total surface area:

\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)

8 0
2 years ago
Suppose you are driving 60 miles per hour. what is your rate of speed in miles per minute?
Verdich [7]

So if it is 60 miles per hour it is basically 60 miles per 60 minutes. \frac{60}{60} when you simplify it, it is going to be 1/1=1 The answer is 1 mile per minute

6 0
3 years ago
Read 2 more answers
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