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Studentka2010 [4]
3 years ago
10

What is the square root of 655.36​

Mathematics
2 answers:
astraxan [27]3 years ago
8 0

Answer:

25.6 this will be the answer

Step-by-step explanation:

Hope it helps

slega [8]3 years ago
3 0

Answer: 25.6

Step-by-step explanation: Have an Amazing Day :)

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5 cakes cost £2.50 how much do 7 cakes cost?
ElenaW [278]
1 cake cost =2.50 divide by 5 = 0.50p

7 cakes cost = 50p times 7 =  £3.50

answer = £3.50

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45+23 div 2 times 2<br> IQ level 200
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Step-by-step explanation:

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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x
Andrei [34K]

Answer:

\large\boxed{A.\ (x+6)^2+(y+10)^2=20}

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

Substitute:

x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute (-6, -10) and (-8, -6):

r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}

Finally we have

(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20

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