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artcher [175]
3 years ago
6

Pls help me I really need help on this

Mathematics
1 answer:
Svetlanka [38]3 years ago
7 0

Answer:

c

Step-by-step explanation:

i just took the test

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Solve for x. Round to the nearest hundredth if necessary.
I am Lyosha [343]

Answer:

Step-by-step explanation:

\frac{19}{x} = tan 29°

x = \frac{19}{tan29^o} ≈ 34.28

4 0
2 years ago
A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra
Harman [31]

Answer:

<em>A.</em>

<em>The student made an error in step 3 because a is positive in Quadrant IV; therefore, </em>

<em />cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}

Step-by-step explanation:

Given

P\ (a,b)

r = \± \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

r = \sqrt{(a)^2 + (b)^2}

Since a belongs to the x axis and b belongs to the y axis;

cos\theta is calculated as thus

cos\theta = \frac{a}{r}

Substitute r = \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}

cos\theta = \frac{a}{\sqrt{a^2 + b^2}}

Rationalize the denominator

cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}

cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}

So, from the list of given options;

<em>The student's mistake is that a is positive in quadrant iv and his error is in step 3</em>

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Katena32 [7]

Answer:

it is six fifths your welcome

Step-by-step explanation:

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Is 88,490,144 divisible by 9?
Vlad [161]

Answer:

No

Step-by-step explanation:

The sum of the digits is 40 which is not divisible by 9, so it is not divisible by 9

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3 years ago
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What is: <br> 8x - 2(4 + 3x)
Angelina_Jolie [31]
8x-2(4+3x) =0\\ 8x-8-6x=0 \\ 2x-8=0 \\ 2x=8 \\ x=4
6 0
3 years ago
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