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lesya [120]
3 years ago
7

Why does Brainly not have a astronomy section. (I'd prefer brainly answer this)

Computers and Technology
1 answer:
elena55 [62]3 years ago
6 0
Could you by any chance help me with my business work?! Please go to my profile and go to the questions that have the subject business!
You might be interested in
Using truth table, prove that:<br><br> (A + B). C = (A . C)+ (B .C) ?
Genrish500 [490]

Answer:

The image of truth table is attached.

Explanation:

In the truth table there is a separate table for the expression (A+B).C and for the expression (A.C)+(B.C) you can see in the truth table that the columns of (A+B).C is having same values as the (A.C)+(B.C).Hence we can conclude that (A+B).C is equal to (A.C)+(B.C).

4 0
3 years ago
What is an XML-based open standard for exchanging authentication and authorization information and is commonly used for web appl
nalin [4]

Answer:

SAML.

Explanation:

SAML seems to be an accessible standardized XML-based for some of the sharing of validation and verification details and has been generally implemented for the web apps and it seems to be a design that would be SSO. Verification data is shared via XML documentation which are securely signed. So, the following answer is correct according to the given scenario.

4 0
3 years ago
Write a program that simulates flipping a coin repeatedly and continues until three consecutive heads. are tossed. At that point
quester [9]

Answer and Explanation:

#include <iostream>

#include <string>

#include <time.h>

#include <vector>

using namespace std;

//Takes user info

int user_info(string *name,char *gender){

   char G;

   cout<<"What is your name?: ";

   getline(cin, *name);

   cout<<"What is your gender(m/f):";

   cin>>G;

   cout<<endl;

   *gender = tolower(G);

   return 0;

}

//Toss coin(part 2)

bool coin_toss(double seed){

   double r;

   r = (double)seed/(double)RAND_MAX;

   //cout<<r;

   if (r<0.5) return true;

   return false;

}

//check results

float toss_result(vector<char> v,int *h){

   int num_heads=0;

   int num_toss = v.size();

   *h = 0;

   for(int i=0;i<num_toss;i++){

       if(v[i]=='h'){num_heads++;(*h)++;}

   }

   return (float)num_heads/(float)num_toss;

}

void show_result(int total_num,int head_num,float ratio){

   cout<<"it took you "<<total_num<<" tosses to get 3 heads in a row"<<endl;

   cout<<"on average you flipped heads "<<(ratio*100)<<"% of the time"<<endl;

}

int main()

{

   string name;

   char gender;

   string K; //Mr or Mrs

 

   cout<<"Welcome to coin toss! Get 3 heads in row to win!"<<endl;

 

   //part 1

   user_info(&name,&gender);

 

   if(gender == 'f') K = "Mrs.";

   else K = "Mr.";

 

   cout<<"Try to get 3 heads in a row. Good luck "<<K<<name<<"!"<<endl;

   char dummy = getchar();

 

   //part 2

   int num_toss;

   vector<char> toss_results;//store toss results

   bool result;//result of toss

   srand(time(0));

   while(true){

       //cout<<rand()<<endl;

       result = coin_toss(rand());

       cout<<"Press <enter> to flip"<<endl;

       while (1)

       {

           if ('\n' == getchar())

           break;

       }

     

 

     

       if(result) {toss_results.push_back('h');cout<<"HEAD"<<endl;}

       else {toss_results.push_back('t');cout<<"TAIL"<<endl;}

     

       num_toss = toss_results.size();

     

       if(num_toss>=3){

           if ((toss_results[num_toss-1] == 'h')&&(toss_results[num_toss-2] == 'h')&&(toss_results[num_toss-3] == 'h')){

               break;

           }

       }

   }

 

   //part 3

   float ratio_head;

   int num_of_heads;

   ratio_head = toss_result(toss_results,&num_of_heads);

 

   //part 4

 

   show_result(toss_results.size(),num_of_heads,ratio_head);

 

   return 0;

}

8 0
3 years ago
In Python please.
SOVA2 [1]

Answer:

negatives = []

zeros = []

positives = []

while True:

   number = input("Enter a number: ")

   if number == "":

       break

   else:

       number = int(number)

       if number < 0:

           negatives.append(number)

       elif number == 0:

           zeros.append(number)

       else:

           positives.append(number)

for n in negatives:

   print(n)

for z in zeros:

   print(z)

for p in positives:

   print(p)

Explanation:

Initialize three lists to hold the numbers

Create a while loop that iterates until the user enters a blank line

Inside the loop:

If the number is smaller than 0, put it in the negatives list

If the number is 0, put it in the zeros list

Otherwise, put the number in the negatives list

When the while loop is done, create three for loops to print the numbers inside the lists

5 0
3 years ago
Which of the following rules should be used to keep the appropriate distance between your vehicle and the vehicle in front of yo
S_A_V [24]
I would say two car length rule. I am not sure what the official license rule is or if it has been changed, but originally the rule was 3 seconds usually depending on how fast the car is going. The faster you are going, the longer it takes to stop. So two-car length rule would probably be the best choice. Definitely not A.
8 0
3 years ago
Read 2 more answers
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