Which is the least valid way to stimulate how many boys and girls are in a random sample of 20 students from a school that is ha
lf boys and half girls?
A. Flip a coin 20 times, assigning one out come to boys and the other to girls
B. Drop 20 coin at once and count the number of each outcome
C. Count how many boys and girls are in your mat class and use a proportion
D. Have a calculator generate 20 random integers and count the number of even and odd integers
2 answers:
Total number of Student in the School in which half are boys and Half are girls =20
Probability of an event
Probability of Number of Boys as well as Probability of Number of Girls
The Most appropriate option is
Option C
Count how many boys and girls are in your math class and use a proportion.
In Option A, B and D
The probability of each outcome that is Success and Failure will be nearly equal to 0.50 .
But in Option C, you can't say precisely that Probability will be equal to , 0.50 in each case , that is Success and Failure.
You might be interested in
This is your answer say me if I am wrong
Answer:
10.5
Step-by-step explanation:
To square a number means to multiply it by itself. So 9 squared would be:
9x9
Which is
81
I hope this Helps!
Answer: 6.65
Step-by-step explanation:
3 4/5 = 3.8
1 3/4 = 1.75
3.8*1.75= 6.65
Hope it helps <3
All we have to do here is divide how much she paid ($1.15) by how many pounds of dried fruit she bought (2.5 pounds)
1.15 ÷ 2.5 = 0.46
Therefore each pound costs $0.46
Hope this helps
-AaronWiseIsBae