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a_sh-v [17]
3 years ago
5

Which is the least valid way to stimulate how many boys and girls are in a random sample of 20 students from a school that is ha

lf boys and half girls?
A. Flip a coin 20 times, assigning one out come to boys and the other to girls

B. Drop 20 coin at once and count the number of each outcome

C. Count how many boys and girls are in your mat class and use a proportion

D. Have a calculator generate 20 random integers and count the number of even and odd integers
Mathematics
2 answers:
slamgirl [31]3 years ago
8 0
I think the answer is C
tensa zangetsu [6.8K]3 years ago
5 0

Total number of Student in the School in which half are boys and Half are girls =20

Probability of an event

             =\frac{\text{Total favorable oucome}}{\text{Total Possible outcome}}                  

Probability of Number of Boys as well as Probability of Number of Girls

                               =\frac{10}{20}\\\\=\frac{1}{2}  

The Most appropriate option is

Option C

Count how many boys and girls are in your math class and use a proportion.

In Option A, B and D

The probability of each outcome that is Success and Failure will be nearly equal to 0.50 .

But in Option C, you can't say precisely that Probability will be equal to , 0.50 in each case , that is Success and Failure.

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Step-by-step explanation:

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Step-by-step explanation:

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Graph the function f(x) = x3 – 5x2 + 6x using the graphing calculator. What are the solutions to the related equation? Check all
Juli2301 [7.4K]

the solutions to the related equation are 0,2,3 .

<u>Step-by-step explanation:</u>

Here we have , function  f(x) = x3 – 5x2 + 6x . Graph of this function is given below  . We need to find What are the solutions to the related equation . Let's find out:

Solution of graph means the  value of x at which the value of f(x) or function is zero . We can determine this by seeing the graph as at what value of x does the graph intersect or cut x-axis !

At x = 0 .

From the graph , at x=0 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 0^3- 5(0)^2 + 6(0)

⇒ f(0) =0

At x = 2 .

From the graph , at x=2 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 2^3- 5(2)^2 + 6(2)

⇒ f(0) =0

At x=3 .

From the graph , at x=3 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 3^3- 5(3)^2 + 6(3)

⇒ f(0) =0

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Answer:

if a water pipe bursts over night depends on the pressure of the water but i will say a foot or more an hour

Step-by-step explanation:

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I need to know how to describe the parts of the expression (3x-2)
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Answer:

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