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nikklg [1K]
3 years ago
12

Two fifths of one less than a number is less than three fifths of one more than that number .what numbers are in the solution se

t of this problem?
Mathematics
1 answer:
Lelechka [254]3 years ago
5 0

2/5(x - 1) < 3/5(1 + x)

To find the solution, we can use the distributive property to simplify.

2/5x - 2/5 < 3/5 + 3/5x

Multiply all terms by 5.

2x - 2 < 3 + 3x

Subtract 2x from both sides.

-2 < 3 + x

Subtract 3 from both sides.

-5 < x

<h3><u>The value of x is greater than the value of -5.</u></h3>
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Pls help I will appreciate it what do I write in box I’m having hard time
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Answer:

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8 0
3 years ago
Please can someone round this to the nearest thousands (2996)​
slamgirl [31]

Answer:

3000

Step-by-step explanation:

it is very simple as the number's hundredth place is more than 5 , hence , it will be rounded up to nearest greater number.

in our case, it is 3000

7 0
3 years ago
Can someone please help me?
andrew11 [14]

Answer:

2/5 so 4/10

THE ANSWER IS A

5 0
4 years ago
Read 2 more answers
Part 1: Identify the vertex, focus, and directrix of each. Then sketch the graph.
Lina20 [59]

Answer:  \bold{1.\quad \text{Vertex}:(4,-1)\qquad \text{Focus}:\bigg(4,-\dfrac{9}{8}\bigg)\qquad \text{Directrix}:y=-\dfrac{7}{8}}

                \bold{2.\quad \text{Vertex}:(2,1)\qquad \text{Focus}:\bigg(\dfrac{9}{4},1\bigg)\qquad \text{Directrix}:y=\dfrac{7}{4}}            

<u>Step-by-step explanation:</u>

The vertex form of a parabola is y = a(x - h)² + k  or  x = a(y - k)² + h

  • (h, k) is the vertex
  • p is the distance from the vertex to the focus
  • -p is the distance from the vertex to the directrix

    \bullet\quad a=\dfrac{1}{4p}

1) y = -2(x - 4)² - 1     →      a = -2   (h, k) = (4, -1)

a=\dfrac{1}{4p}\quad \rightarrow \quad -2=\dfrac{1}{4p}\quad \rightarrow \quad p=-\dfrac{1}{8}\\\\\text{Focus = Vertex + p}\\\\.\qquad = \dfrac{-8}{8}+\dfrac{-1}{8}\\\\.\qquad =-\dfrac{9}{8}\qquad \rightarrow \qquad \text{Focus}=\bigg(4,-\dfrac{9}{8}\bigg)\\\\\\\text{Directrix: y=Vertex - p}\\\\.\qquad \qquad y=\dfrac{-8}{8}-\dfrac{-1}{8}\\\\.\qquad \qquad y=-\dfrac{7}{8}

*******************************************************************************************

2) x = (y - 1)² + 2     →      a = 1   (h, k) = (2, 1)

a=\dfrac{1}{4p}\quad \rightarrow \quad 1=\dfrac{1}{4p}\quad \rightarrow \quad p=-\dfrac{1}{4}\\\\\text{Focus = Vertex + p}\\\\.\qquad = \dfrac{8}{4}+\dfrac{1}{4}\\\\.\qquad =\dfrac{9}{4}\qquad \rightarrow \qquad \text{Focus}=\bigg(\dfrac{9}{4},1\bigg)\\\\\\\text{Directrix: x=Vertex - p}\\\\.\qquad \qquad x=\dfrac{8}{4}-\dfrac{1}{4}\\\\.\qquad \qquad x=\dfrac{7}{4}

6 0
3 years ago
What is the range of f(x) = 3/4x -4
shusha [124]

Answer:

The range is the resulting y-values we get after substituting all the possible x-values.

For the given function : f(x) = \frac{3}{4x} -4

<u>See the attached figure.</u>

The zeros of the denominator at x = 0

The domain is: (-∞,0)∪(0,∞)

<u>The range</u> of the function is the domain of the inverse function of f(x)

y = 3/(4x) - 4

y + 4 = 3/(4x)

4x = 3/(y+4)

x=\frac{3}{4(y+4)}

The zeros of the inverse function:

4(y+4) = 0

y + 4 = 0

y = -4

∴ The range is (-∞,-4)∪(-4,∞)

So, the answer is {y | y > –4} ∪ {y | y < – 4}

=========================================

<u>Note</u>: If the given function is : f(x) = \frac{3}{4} x-4

It will be first degree polynomial function.

Both of the domain and the range = all real numbers R

4 0
4 years ago
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