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Varvara68 [4.7K]
3 years ago
12

Jackie's dad drives her to a friend's house at the speed 30 mph. The friend's mom drives her back using the same route at the sp

eed 25 mph. If the way back takes 6 minutes longer how far away is the friend's house?
Mathematics
1 answer:
kvv77 [185]3 years ago
5 0

Answer:

The distance to Jackie's friend house is 15 miles

Step-by-step explanation:

The given parameters are outlined as follows;

1) The speed with which Jackie's dad drove her to her friends house = 30 mph

2) The speed Jackie's fiend mom drove her back home on the same route = 25 mph

The time it takes Jackie's friend mom to drive her back home = 6 minutes + The time it took Jackie's dad drove her to her friends house

Let the time, in minutes, it took Jackie's dad drove her to her friends house = t

Therefore;

The time it takes Jackie's friend mom to drive her back home = 6 + t

We have that speed = Distance/Time

∴ For Jackie's friend mom, her speed of 25 mph = (The distance of Jackie's friend house)/(6 + t)

Which gives;

The distance of Jackie's friend house = 25 × (6 + t)

Similarly, for Jackie's dad, his speed of 25 mph = (The distance of Jackie's friend house)/t

Which gives;

The distance of Jackie's friend house = 30 × t

By substitution, we have;

The distance of Jackie's friend house = 25 × (6 + t) = 30 × t

By the distributive property, we have;

150 + 25·t = 30·t

150 = 30·t - 25·t = 5·t

150 = 5·t

t = 150/5 = 30 minutes

t = 30 = 0.5 Hours

Using the equation for the distance to Jackie's friend house derived with the speed of motion of Jackie's dad, we have

The distance to Jackie's friend house = 30 × t = 30 mi/h × 0.5 h = 15 mi

The distance to Jackie's friend house = 15 miles

Similarly, from the equation derived from the speed of motion of Jackie's friend mom, we have;

The distance to Jackie's friend house = 25 × (6 + t) = 25 × (6 + 30)

The distance to Jackie's friend house = 25 mph × 36 minutes

The distance to Jackie's friend house = 25 miles per hour × 0.6 hours = 15 miles

The distance to Jackie's friend house = 15 miles.

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Answer:

a) P(X < 99) = 0.2033.

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

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3 years ago
A school requires an entrance exam score that is in the top 3% of the population in order to be accepted. If an entrance exam ha
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The answer is letter C.) 603.40

The minimum required score can solved using the equation
<span>MRS = mean + (zscore)(SD)

where z score of 0.03 is 1.88

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</span>

<span>Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.</span>

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Step-by-step explanation:

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y-y_1=m(x-x_1)

Plug in the values into the equation

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To solve for x-intercept , Arrange the values in

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To find x-intercept .let y = 0 in the above equation

-  \frac{2}{3} x - y +  \frac{4}{3}  = 0 \\  -  \frac{2}{3} x - 0 +  \frac{4}{3}  = 0 \\

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Solve for x ;

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I hope it helps <3

7 0
3 years ago
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Hey!
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3 years ago
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maks197457 [2]
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