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ANEK [815]
3 years ago
7

I dont know how to solve this

Mathematics
2 answers:
Drupady [299]3 years ago
8 0
1) x²+25
2)121-a²
3)2x²+5476
4)9m+16-12m-12m
-15m+16
5)81+16h-36h-36h
81-56h
not pretty sure tho
never [62]3 years ago
5 0
For the first question
Split them into 2 brackets as they are squared e.g. (x+5)(x+5)

And then multiply out the brackets e.g. x^2+5x+5x+25

Then collect like terms e.g.
x^2+10x+25

Then you should be able to figure out the next few questions
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Can someone please help me with this math question?
Ivan
V=(22-2t)(15-2t)(12-2t) and we are told the thickness is 1/2 so

V=(21)14(11)=3234in^3

B :)
6 0
3 years ago
I NEED HELP PLEASSSEEEE!!!
Nookie1986 [14]

So the answer is 30, explanation in the picture

8 0
4 years ago
4(x – 5) +2x = -14<br> So x=?
Nikolay [14]

Answer:

x=1

Step-by-step explanation:

Step 1:Simplify both sides of the equation

4(x-5)+2x=-14

(4)(x)+(4)(-5)+2x=-14

4x+-120+2x=-14

4x+2x+-20-14

6x+-20=-14

6x-20=-14

Step 2: Add 20 to both sides

6x-20+20=-14+20

6x=6

Step 3: Divide both sides by 6

6x/6=6/6

x=1

4 0
3 years ago
Find three consecutive even integers such that six times the sum of the first and the third is twenty - four greater than eleven
dedylja [7]

Answer:

1st = 22

2nd = 24

3rd = 26

Step-by-step explanation:

1st = x

2nd = x +2

3rd = x + 4

6(x + x + 4) = 24 + 11(x + 2)

6(2x + 4) = 24 + 11x + 22

12x + 24 = 46 + 11x

x + 24 = 46

x = 22

x + 2 = 24

x + 4 = 26

8 0
3 years ago
Please help it’s due!
BigorU [14]

Answer:

Step-by-step explanation:

H

7 0
3 years ago
Read 2 more answers
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