Question

Solve the system of linear equations below, using substitution method.

Answer 1

Answer:

The solution is (0,4).

Step-by-step explanation:

We are given the following system of equations:

$8x + 9y = 36$

$3x + 4y = 16$

Solving by substitution.

In the first equation, we have that:

$8x + 9y = 36$

$8x = 36 - 9y$

$x = \frac{36-9y}{8}$

Replacing in the second equation:

$3x + 4y = 16$

$3\frac{36-9y}{8} + 4y = 16$

Multiplying everything by 7

$3(36 - 9y) + 32y = 128$

$108 - 27y + 32y = 128$

$5y = 20$

$y = \frac{20}{5}$

$y = 4$

Now, with y, we can find x.

$x = \frac{36-9*4}{8} = 0$

So the solution is (0,4).