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Alex_Xolod [135]
3 years ago
15

In the circle below, suppose m FEH=272º and m EFG=116º. Find the following.​

Mathematics
1 answer:
adoni [48]3 years ago
5 0

Answer:

m∠FEH = 44°

m∠EHG =  64°

Step-by-step explanation:

1) The given information are;

The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°

Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°

Therefore, angle subtended by arc ∠HGF at the center = 88°

The angle subtended by arc ∠HGF at the circumference = m∠FEH

∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)

m∠FEH = 44°

2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°

The sum of angles in a quadrilateral = 360°

Therefore;

m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)

m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°

m∠EHG =  64°.

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Answer:

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We know than tan(x) = opposite/adjacent, so tan(x) here = 8000/16000 = 1/2. Then, arctan(1/2) =x = 27 degrees

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Ixl help I’m tryna reach a smart score of 50
Sergeeva-Olga [200]

Answer:

The interest is equal to \$13$13

we know that

The compound interest formula is equal to

A=P(1+\frac{r}{n})^{nt}A=P(1+

n

r

)

nt

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

\begin{gathered}t=3\ years\\ P=\$80\\ r=0.05\\n=1\end{gathered}

t=3 years

P=$80

r=0.05

n=1

substitute in the formula above

A=\$80(1+\frac{0.05}{1})^{3}=\$92.61A=$80(1+

1

0.05

)

3

=$92.61

Find the interest

I=A-P=\$92.61-\$80=\$12.61I=A−P=$92.61−$80=$12.61

Round to the nearest whole dollar

\$12.61=\$13$12.61=$13

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