Answer: 11.78
Step-by-step explanation: You have to minus 36 by the cost of the hat and sunglasses.
Answer:
Number of children = 386
Number of adults = 287
Step-by-step explanation:
Let
x = number of children
y = number of adults
x + y = 673 (1)
1.75x + 2y = 1249.50 (2)
From (1)
x = 673 - y
Substitute x = 673 - y into (2)
1.75x + 2y = 1249.50
1.75(673 - y) + 2y = 1249.50
1177.75 - 1.75y + 2y = 1249.50
- 1.75y + 2y = 1249.50 - 1177.75
0.25y = 71.75
y = 71.75/0.25
y = 287
Substitute y = 287 into (1)
x + y = 673
x + 287 = 673
x = 673 - 287
x = 386
Number of children = 386
Number of adults = 287
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
The equation of the function is y = 4x + 5. Find the value of y when
x = 3
x = -2
<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>
<h3>Given:-</h3>
y = 4x + 5 [Equation]
<h3>To Find:-</h3>
The value of y when x = 3 , x = -2
<h2>Solution:-</h2>
y = 4x + 5 [Given equation]
When x = 3 ,
y = 4 × 3 + 5 [Value of x is 3]
y = 12 + 5
<h3>y = 17 [Answer]</h3>
Again, when x = -2 ,
y = 4 × (-2) + 5 [Value of x is -2]
y = -8 + 5
<h3>y = -3 [Answer]</h3>
Answer:
x + 0.07x ≥ 30
Step-by-step explanation:
A sum is terms separated by a plus sign.
"Is at least" means "is greater than or equal to."
7% as a decimal fraction is 0.07.
"Of" means "times."
__
In consideration of the above, you have ...
x plus 7% of x is at least 30
x + 0.07x ≥ 30 . . . . . using math symbols
Answer:
≈ -5.1857
≈ -5.4857
≈ 3.7262
Step-by-step explanation:
Rewrite the equation system as:



Now, write the system in its augmented matrix form:
![\left[\begin{array}{cccc}6&8&0&-75\\-3&6&6&5\\2&-9&0&39\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D6%268%260%26-75%5C%5C-3%266%266%265%5C%5C2%26-9%260%2639%5Cend%7Barray%7D%5Cright%5D)
applying row reduction process to its associated augmented matrix:
Swap R1 and R3, and then Swap R1 and R2:
![\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\6&8&0&-75\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C2%26-9%260%2639%5C%5C6%268%260%26-75%5Cend%7Barray%7D%5Cright%5D)
R3+2R1
![\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\0&20&12&-65\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C2%26-9%260%2639%5C%5C0%2620%2612%26-65%5Cend%7Barray%7D%5Cright%5D)
3R2+2R1
![\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&20&12&-65\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C0%26-15%2612%26127%5C%5C0%2620%2612%26-65%5Cend%7Barray%7D%5Cright%5D)
15R3+20R2
![\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&0&420&1565\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C0%26-15%2612%26127%5C%5C0%260%26420%261565%5Cend%7Barray%7D%5Cright%5D)
Now we have a simplified system:


From (3):
(4)
Replacing (4) in (2)
(5)
Finally replacing (5) and (4) in (1)
