Answer:
<u>There are:</u>
- 6 red balls - R
- 5 black balls - B
- Total number = 11 balls
<h3>A. Without replacement</h3>
i. <u>Two blacks </u>
ii. <u>The first is black</u>
or, alternatively
- P(BR or BB) = 5/11*6/10 + 2/11 = 3/11 + 2/11 = 5/11
iii. <u>Both are of same colour</u>
- P(BB or RR) = 2/11 + 6/11*5/10 = 2/11 + 3/11 = 5/11
<h3>B. With replacement</h3>
i. <u>Two blacks </u>
- P(BB) = 5/11*5/11 = 25/121
ii. <u>The first is black</u>
or alternatively
- P(BR or BB) = 5/11*6/11 + 25/121 = 30/121 + 25/121 = 55/121 = 5/11
iii. <u>Both are of same colour</u>
- P(BB or RR) = 5/11*5/11 + 6/11*6/11 = 25/121 + 36/121 = 61/121
Answer:
x ≈ 1091.63
Step-by-step explanation:
Using the rule of logarithms
x = n ⇔ x = 
note that ln x is to the base e
Given
ln(x + 5) = 7, then
x + 5 = 
( subtract 5 from both sides )
x = - 5 ≈ 1091.63 ( nearest hundredth )
Answer:
<h2>(-4,-2)</h2>
Step-by-step explanation:
(-4,-5)
move up 3 units
change in y-axis
-5+3=-2
(-4,-2)
Answer: Gear 14 or 14.3
Step-by-step explanation:
