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Zanzabum
3 years ago
7

Solve for the distance from point A to point B. Round your answer to

Mathematics
1 answer:
Cloud [144]3 years ago
6 0

Answer:

11.4

Step-by-step explanation:

Distance Formula: d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

1. d=\sqrt{(-4-5)^2+(-3-4)^2}

2. d=\sqrt{(-9)^2+(-7)^2}

3. d=\sqrt{81+49}

4. d=\sqrt{130}

5. d=11.4017

6. d=11.4

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The product of a number and 50
Daniel [21]
"Product" means we are looking at a multiplication problem.

Can be written as: 

A number (n) times 50

n x 50

The simplest (and most common way) to write it:

50n
4 0
3 years ago
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The perimeter of a square is 4 times the length of one side of the square. Which graph represents this situation? *
Arisa [49]

Answer:

A.

Step-by-step explanation:

Graph B must be incorrect as this is a directly proportional relationship. Likewise, graph C shows an inversely proportional relationship.

Between graph A and D, only graph A passes through the origin, which is true because if length is zero, perimeter is zero.

Hence the answer is Graph A.

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The graph of y = x^2 is translated 3 units to the left. The equation for this new graph is:
EastWind [94]
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7 0
3 years ago
I need 6x-10 ima not too good with these
Verizon [17]

x=11

the angles are congruent so 6x-10=56

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x=11

5 0
3 years ago
12What mistake did the student make when solvingtheir two-step equation?(a)b) If correctly solved what should the value of be?
mixas84 [53]

Given the equation:

\frac{x}{6}+3=-18

(a) You can identify that the student applied the Subtraction Property of Equality by subtraction 3 from both sides of the equation:

\frac{x}{6}+3-(3)=-18-(3)

However, the student made a mistake when adding the numbers on the right side.

Since you have two numbers with the same sign on the right side of the equation, you must add them, not subtract them and use the same sign in the result. Then, the steps to add them are:

- Add their Absolute values (their values without the negative sign).

- Write the sum with the negative sign.

Then:

\frac{x}{6}=-21

(b) The correct procedure is:

1. Apply the Subtraction Property of Equality by subtracting 3 from both sides (as you did in the previous part):

\begin{gathered} \frac{x}{6}+3-(3)=-18-(3) \\  \\ \frac{x}{6}=-21 \end{gathered}

2. Apply the Multiplication Property of Equality by multiplying both sides of the equation by 6:

\begin{gathered} (6)(\frac{x}{6})=(-21)(6) \\  \\ x=-126 \end{gathered}

Hence, the answers are:

(a) The student made a mistake by adding the numbers -18 and -3:

-18-3=-15\text{ (False)}

(b) The value of "x" should be:

x=-126

4 0
1 year ago
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