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3 years ago

40oz= lb need to be converted

Mathematics

2 answers:

alekssr [168]3 years ago

4 0

The answer is 2.5 pounds.

bija089 [108]3 years ago

3 0

2.5 pounds is the answer

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Can a right triangle have two angles that measure 25 and 65

Art [367]

Yes, because there would only be 1 right triangle and all the angles need to add up to 180 degrees and 90+25+65=180.

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4 years ago

What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (−4,

Stells [14]

Writing it in perpendicular form is easy as 1, 2, 3.

First you should put it in y = mx + b Form (Slope intercept)

#1: y = x + 7

Simply flip the reciprocals

#2: y = -x + 7

7 0

3 years ago

Philip ran 4 3/8 miles yesterday. Michael ran 1 5/8 miles yesterday.

deff fn [24]

Answer:

2 7/8

Step-by-step explanation:

3 0

3 years ago

Which is the intersection of the sets {0, 1, 5, 7, 8} and {0,5,7,9}?

grigory [225]

Answer:

Step-by-step explanation:

Intersection set will contain the data that are found in both the sets

A = { 0 , 1 ,5 ,7,8}

B= {0,5,7,9}

A ∩ B = {0,5,7}

5 0

2 years ago

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

3 years ago