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3 years ago

Choose an appropriate metric unit mass for an bottle of ink

Mathematics

2 answers:

fenix001 [56]3 years ago

7 0

Answer:

gram

Step-by-step explanation:

Which of these units is most appropriate for expressing the metric mass of a bottle of ink?

Eliminate meter; that's a unit of distance

Gram is correct; it's a measure of mass in small but not microscopic quantities

Eliminate millimeter; it's a unit of length or distance, not of mass

Elimin. liter: that's a measure of liquid volume.

solniwko [45]3 years ago

3 0

Answer:

B. gram

Step-by-step explanation:

A meter is a unit for measuring length

A millimeter is a unit for measuring length

A liter also is a metric unit for mass, however it is too large for a bottle of ink

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An electrician charges $322 for 7 hours of work. How much does the electrician charge for one hour?

In-s [12.5K]

Answer:

About 46 dollars an hour

Step-by-step explanation:

322/7 = 46

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3 years ago

Index notation simplify 4^9 x 4^3

LenKa [72]

Answer:

$4^{12}$

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , then

$4^{9}$ × $4^{3}$ = $4^{(9+3)}$ = $4^{12}$

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3 years ago

Simplify the expression -2/3 divided by 3 3/4

Vitek1552 [10]

Answer:

-8/45

I hope this helped!

Step-by-step explanation:

-2/3 ÷ 3 3/4

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3 years ago

A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a

netineya [11]

Answer:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=19, p=0.3)$