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3 years ago

If the weights of 1,000 adult men in a county are plotted on a histogram, which curve is most likely to fit the histogram?

2 answers:

8 0

The correct answer for the question that is being presented above is this one: "C. a bell-shaped curve, better known as a normal distribution." If the weights of 1,000 adult men in a county are plotted on a histogram, the curve will most probably be a bell-shaped curve, better known as a normal distribution.

Here are the following choices:
<span>A. a U-shaped curve, better known as a normal distribution
B. a star-shaped curve, better known as a normal distribution
C. a bell-shaped curve, better known as a normal distribution
D. a bell-shaped curve, known as an exponential distribution</span>

12345 [234]3 years ago

6 0

Answer: C) a bell-shaped curve, better known as a normal distribution

Step-by-step explanation:plato only

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32+2/3(21y-6) in factored form

artcher [175]

Answer:

14(y + 2).

Step-by-step explanation:

32 +2/3(21y - 6)

Distributing the 2/3 over the parentheses:

= 32 + 2/3*21y + 2/3 * -6

= 32 + 14y - 4

= 14y + 28

= 14(y + 2).

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2 years ago

Segment Addition Postulate<br> Using the following image, solve for x.

Aleks04 [339]

Answer:

Here,

CD + DE = CD

x+10 + x+4 = 8

2x + 14 = 8

2x= -6

x= -3

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2 years ago

Which of the following functions are solutions of the differential equation y'' + y = 3 sin x? (select all that apply)

DiKsa [7]

Answer:

Step-by-step explanation:

We must compute the derivatives and check if the equation is satisfied.

A. $y'=(3\sin x)'=3\cos x$ . Differentiate again to get $y''=(3\cos x)'=-3\sin x$ , then $y''+y=-3\sin x+3\sin x=0\neq 3\sin x$ so this choice of y doesn't solve the equation.

B. $y'=3\sin x+3x\cos x-5\cosx +5x\sin x=(5x+3)\sin x+(3x-5)\cos x$ and $y''=5\sin x+(5x+3)\cos x+3\cos x-(3x-5)\sin x=(10-3x)\sin x+(5x+6)\cos x$ , then $y''+y=10\sin x+6\cos x\neq 3\sin x$ so y is not a solution

C. $y'=\frac{-3}{2}\cos x+\frac{3}{2}x\sin x$ hence $y''=\frac{3}{2}\sin x+\frac{3}{2}\sin x+\frac{3}{2}x\cos x=3\sin x+\frac{3}{2}x\cos x$ . Then $y''+y=3\sin x+\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\sin x$ so y is a solution.

D. $y'=-3\sin x$ and $y''=-3\cos x$ , then $y''+y=0$ thus y isn't a solution

E. $y'=\frac{3}{2}\sin x+\frac{3}{2}x\cos x$ hence $y''=\frac{3}{2}\cos x+\frac{3}{2}\cos x-\frac{3}{2}x\sin x=3\cos x-\frac{3}{2}x\cos x$ . Then $y''+y=3\cos x-\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\cos x\neq 3\sin x$ then y is not a solution.

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3 years ago

Find the perimeter of the figure

SashulF [63]

To solve this, find the rest of the sides:

The other sides are:

1. 24 - 8 = 16
2. 23 - 9 = 14

Next, just add it up:

24 + 9 + 16 + 14 + 8 + 23 = 33 + 30 + 31 = 94

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3 years ago

The gym is filled with 215 students & adults. Student tickets are $.50 and adults are $2.00. If $250.00 was collected, how m

BARSIC [14]

In order to determine the correct answer, it would be helpful to set up equations. We do as follows:

Let x = students
y = adults

x + y = 215
.50x + 2y = 250

SOlving simultaneously, we have:

x = 120 students
y = 95 adults

Hope this answers the question. Have a nice day.

3 0

2 years ago