All categories

3 years ago

A number minus 8 is the same as a number n divided by 2.

Mathematics

2 answers:

Ivenika [448]3 years ago

7 0

the number is 16

hope it helps

plz plz mark brainliest

Vaselesa [24]3 years ago

4 0

<h3><u>Given</u> :</h3>

A number minus 8 is the same as a number divided by 2.

We have to find that number $.$

<h3><u>Solution</u> :</h3>

Let the number be x.

From the given question,

1. Number minus 8

x - 8 ..... (I)

2. Number divided by 2

x/2 ..... (II)

ATQ : (I) = (II)

⭆ x - 8 = x/2

⭆ 2(x -8) = x

⭆ 2x - 16 = x

⭆ 2x - x = 16

⭆ <u>x = 16</u>

<h3>#CarryOnLearning</h3>

You might be interested in

Please help!!!!!!!!!!!!

boyakko [2]

Answer:

Step-by-step explanation:

2 1/5 is equivalent to 0.022. Yes, 0.0215 is less than 0.022.

This is clearer if you write the two values in a column:

0.0220 (larger than 0.0215)

0.0215 (smaller than 0.0220)

7 0

3 years ago

What is the answer to triple a number is the s game as double the number increased by 5

kramer

Answer:

x = 7

Step-by-step explanation:

Let x = the number. Then

"Triple a number" means 3x

"is the same as" means =

"double the number increased by 5" means 2x + 7

∴ 3x = 2x + 7

Subtract 2x from each side

x = 7

The answer is x = 7.

Check:

3 × 7 = 2 × 7 + 7

21 = 14 + 7

21 = 21

OK.

6 0

3 years ago

ANSWER #3 TO BE MARKED AS BRAINLIEST

12345 [234]

V=9 1/20, because when you multiply 4/5 by 4 and 1/4 by 5 to get a common denominator you get 21/20. You add the 3 and the 5, and add the one we got from the fractions and add the 1/20 to get 9 1/20

5 0

3 years ago

Read 2 more answers

Later, Alexis is looking at a different set of coins: this time only dimes and nickels. She has twice as many nickels as dimes,

musickatia [10]

9514 1404 393

Answer:

16 dimes
32 nickels

Step-by-step explanation:

Consider a group of 1 dime and 2 nickels. The value of it is 0.20. The total value of all such groups is 3.20, so there must be ...

3.20/0.20 = 16 . . . . . groups of coins

That is, there are 16 dimes and 32 nickels.

5 0

2 years ago

Integrala x la a treia ori ln la a doua dx va rog

Studentka2010 [4]

I don't speak Romanian, but the closest translation for this suggests you're trying to compute

$\displaystyle \int x^3 \ln(x)^2 \, dx$

Integrate by parts:

$\displaystyle \int x^3 \ln(x)^2 \, dx = uv - \int v \, du$

where

u = ln(x)² ⇒ du = 2 ln(x)/x dx

dv = x³ dx ⇒ v = 1/4 x⁴

$\implies \displaystyle \int x^3 \ln(x)^2 \, dx = \frac14 x^4 \ln(x)^2 - \frac12 \int x^3 \ln(x) \, dx$

Integrate by parts again:

$\displaystyle \int x^3 \ln(x) \, dx = u'v' - \int v' du'$

where

u' = ln(x) ⇒ du' = dx/x

dv' = x³ dx ⇒ v' = 1/4 x⁴

$\implies \displaystyle \int x^3 \ln(x) \, dx = \frac14 x^4 \ln(x) - \frac14 \int x^3 \, dx$

So, we have

$\displaystyle \int x^3 \ln(x)^2 \, dx = \frac14 x^4 \ln(x)^2 - \frac12 \left(\frac14 x^4 \ln(x) - \frac14 \int x^3 \, dx \right)$

$\displaystyle \int x^3 \ln(x)^2 \, dx = \frac14 x^4 \ln(x)^2 - \frac18 x^4 \ln(x) + \frac18 \int x^3 \, dx$

$\displaystyle \int x^3 \ln(x)^2 \, dx = \frac14 x^4 \ln(x)^2 - \frac18 x^4 \ln(x) + \frac18 \left(\frac14 x^4\right) + C$

$\displaystyle \int x^3 \ln(x)^2 \, dx = \frac14 x^4 \ln(x)^2 - \frac18 x^4 \ln(x) + \frac1{32} x^4 + C$

$\boxed{\displaystyle \int x^3 \ln(x)^2 \, dx = \frac1{32} x^4 \left(8\ln(x)^2 - 4\ln(x) + 1\right) + C}$

3 0

2 years ago