Question

Factor Completely.3g^2-78g+75

Answer 1

Answer:(3g-75)(g-1)

Step-by-step explanation:

3g^2-78g+75

3g^2-3g+75g-75

3g(g-1)+75(g-1)

(3g-75)(g-1)

Answer 2

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❖ 3g^2 - 78g + 75 factored completely is $3(g-1) * (g-25)$

First, write the expression as a difference:

$3(g^{2} -26g +25)$

Then factor the expression:

$3(g^{2} - g - 25g + 25)$

Factor the expression again:

$3 (g*(g-1)-25(g-1))$

Your final answer should be:

$3(g-1)*(g-25)$

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