All categories

2 years ago

Determine x in the figure. 74° 2xº

Mathematics

1 answer:

Monica [59]2 years ago

6 0

Answer:

-37

Step-by-step explanation:

Simplifying

74 + 2x = 0

Solving

74 + 2x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-74' to each side of the equation.

74 + -74 + 2x = 0 + -74

Combine like terms: 74 + -74 = 0

0 + 2x = 0 + -74

2x = 0 + -74

Combine like terms: 0 + -74 = -74

2x = -74

Divide each side by '2'.

x = -37

Simplifying

x = -37

You might be interested in

It would really help if someone could tell me the answers for those questions

vazorg [7]

1) 2.4

2) 6.4

3) 7.7

4) 9.9

5) 2.8

Hope it helps <3

Just basic simplification, make 1 of the variable alone on one side

5 0

3 years ago

Which of the following is true?

Nitella [24]

Answer:

Step-by-step explanation:

because if u add them together you get the answer

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Crm%5Cfrac%7Bd%7D%7Bdx%7D%20%20%20%5Cleft%20%28%20%5Cbigg%28%20%5Cint_%7B1%7D%5E%7B%20%7B

Margaret [11]

Applying the product rule gives

$\displaystyle \frac{d}{dx}\int_1^{x^2}\frac{2t}{1+t^2}\,dt \times \int_1^{\ln(x)}\frac{dt}{(1+t)^2} + \int_1^{x^2}\frac{2t}{1+t^2}\,dt \times \frac{d}{dx}\int_1^{\ln(x)}\frac{dt}{(1+t)^2}$

Use the fundamental theorem of calculus to compute the remaining derivatives.

$\displaystyle \frac{4x^3}{1+x^4} \int_1^{\ln(x)}\frac{dt}{(1+t)^2} + \frac{1}{x(1+\ln(x))^2}\int_1^{x^2}\frac{2t}{1+t^2}\,dt$

The remaining integrals are

$\displaystyle \int_1^{\ln(x)}\frac{dt}{(1+t)^2} = -\frac1{1+t}\bigg|_1^{\ln(x)} = \frac12-\frac1{1+\ln(x)}$

$\displaystyle \int_1^{x^2}\frac{2t}{1+t^2}\,dt=\int_1^{x^2}\frac{d(1+t^2)}{1+t^2}=\ln|1+t^2|\bigg|_1^{x^2}=\ln(1+x^4)-\ln(2) = \ln\left(\frac{1+x^4}2\right)$

and so the overall derivative is

$\displaystyle \frac{4x^3}{1+x^4} \left(\frac12-\frac1{1+\ln(x)}\right) + \frac{1}{x(1+\ln(x))^2} \ln\left(\frac{1+x^4}2\right)$

which could be simplified further.

5 0

2 years ago

The figure on the left represents a scale drawing of the figure on the right. What is the scale?

stich3 [128]

Answer:10

Step-by-step explanation:

7 0

3 years ago

The Venn diagram shows the number of participants in extracurriucular activities for a junior class of 324 students. Determine t

salantis [7]

<h3>Answer: 53/108</h3>

======================================================

Explanation:

Step 1) add up all the values in the circles "drama" and "music". Those values are 51, 15, 12, 11, 7, 63. So we get 51+15+12+11+7+63 = 159. There are 159 students that are in drama, music, or both. Some take athletics as well, but we aren't concerned with that third class.
Step 2) Divide 159 over the total number of juniors, which is 324. We get 159/324.
Step 3) Reduce the fraction 159/324 to get the answer 53/108. You would divide both parts of 159/324 by the GCF 3. So we have 159/3 = 53 and 324/3 = 108

If you want the decimal approximation, then use a calculator to get roughly 53/108 = 0.4907, though your teacher wants the exact fraction form.

5 0

3 years ago