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2 years ago

Solve the following equation: 7/3=y−2/3

Mathematics

2 answers:

Elodia [21]2 years ago

5 0

Y=3 because 7/3 + 2/3 = 9/3= 3

garri49 [273]2 years ago

3 0

Answer:

y = 3

Step-by-step explanation:

Add $\frac{2}{3}$ to both sides of the equation

$\frac{7}{3}+\frac{2}{3}=y-\frac{2}{3}+\frac{2}{3}$

$y =3$

Hence, y =3

[RevyBreeze]

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ankoles [38]

Answer:

2√2

Step-by-step explanation:

We can find the relationship of interest by solving the given equation for A, the mean distance.

<h3>Solve for A</h3>

$T^3=A^2\\\\A=\sqrt{T^3}=T\sqrt{T}\qquad\text{take the square root}$

<h3>Substitute values</h3>

The mean distance of planet X is found in terms of its period to be ...

$D_x=T_x\sqrt{T_x}$

The mean distance of planet Y can be found using the given relation ...

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The mean distance of planet Y is increased from that of planet X by the factor ...

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8 0

2 years ago

A walkway forms one diagonal of a square playground. The walkway is 14 m long. How long is a side of the playground?

Vilka [71]

Answer: The side of the playground is around 10 meters long

Step-by-step explanation:

use the diagonal as the hypotenuse of a right triangle, where the sides of the square form the legs of said triangle.

Usually

$a^{2} +b^{2} =c^{2}$

since we know a and b are the same length (sides of a square are congruent) we would have

$a^{2} +a^{2} =c^{2} \\2a^{2} =c^{2}$

We know that c is 14 so

$2a^{2} =14^{2} \\2a^{2} =196\\a^{2} =98\\a=\sqrt{98} \\a= 9.999$

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2 years ago

John's bank notified him that he had a negative checking account balance of -$125.70. If John makes two deposits of $89.32 each,

NeX [460]

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3 years ago

Someone please help me make a proof for the bottom question

Lerok [7]

Answer:

DB = CA (Proved)

Step-by-step explanation:

Statement 1.

∠D = ∠C, M is the midpoint of DC and ∠1 = ∠2

Reason 1.

Given

Statement 2.

Between Δ DBM and Δ CAM,

(i) DM = CM,

(ii) ∠D = ∠C and

(iii) ∠DMB = ∠CMA

Reason 2.

(i) given

(ii) given and

(iii) ∠ DMB = ∠1 + ∠AMB and ∠CMA = ∠2 + ∠AMB

Since ∠1 = ∠2, so, ∠DMB = ∠CMA.

Statement 3.

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Reason 3.

By angle-side-angle rule.

Statement 4.

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Corresponding sides of two congruent triangles. (Answer)

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3 years ago

Please solve the following sum or difference identity.

xxTIMURxx [149]

Answer:

$sin(A - B) = \frac{4}{5}$

Step-by-step explanation:

Given:

$sin(A) = \frac{24}{25}$

$sin(B) = -\frac{4}{5}$

Need:

$sin(A - B)$

First, let's look at the identities:

sum: $sin(A + B) = sinAcosB + cosAsinB$

difference: $sin(A - B) = sinAcosB - cosAsinB$

The question asks to find sin(A - B); therefore, we need to use the difference identity.

Based on the given information (value and quadrant), we can draw reference triangles to find the simplified values of A and B.

sin(A) = $\frac{24}{25}$

cos(A) = $\frac{7}{25}$

sin(B) = $-\frac{4}{5}$

cos(B) = $\frac{3}{5}$

Plug these values into the difference identity formula.

$sin(A - B) = sinAcosB - cosAsinB$

$sin(A - B) = (\frac{24}{25})(\frac{3}{5}) - (-\frac{4}{5})(\frac{7}{25})$

Multiply.

$sin(A - B) = (\frac{72}{125}) + (\frac{28}{125})$

Add.

$sin(A - B) = \frac{4}{5}$

This is your answer.

Hope this helps!

6 0

3 years ago

Read 2 more answers