Answer: (b)-175 ft
Step-by-step explanation:
In 
![\angle ACB=\angle ECD\quad [\text{vertically opposite angles}]\\\angle ABC=\angle CDE\quad [\text{Each angle is }90^{\circ}]\\\therefore \triangle ABC \sim\ \triangle CDE\quad [\text{by AA similarity criteria}]](https://tex.z-dn.net/?f=%5Cangle%20ACB%3D%5Cangle%20ECD%5Cquad%20%5B%5Ctext%7Bvertically%20opposite%20angles%7D%5D%5C%5C%5Cangle%20ABC%3D%5Cangle%20CDE%5Cquad%20%5B%5Ctext%7BEach%20angle%20is%20%7D90%5E%7B%5Ccirc%7D%5D%5C%5C%5Ctherefore%20%5Ctriangle%20ABC%20%5Csim%5C%20%5Ctriangle%20CDE%5Cquad%20%5B%5Ctext%7Bby%20AA%20similarity%20criteria%7D%5D)
(ii)for similar triangles, we can write
Range is eleven median is 27
Answer:
Use PEMDAS so division would be the first step
Step-by-step explanation:
1)Parentheses
2)Exponents
3)Multiplication
4)Division
5)Addition
6)Subtraction
Answer:
1. Group A and B agree with each other.
2. Group A and C do not agree with each other.
Step-by-step explanation:
When we are analizing this problem, we will see what are the ranges of this measured times. Since we are taking into account the error we can see that :
- Group A varies from 7.34-0.05 to 7.34+0.05. So the limits are (7.29 ;7.39)
- Group B varies from 7.38-0.03 to 7.38+0.03. So the limits are (7.35; 7.41)
- Group C varies from 7.46-0.06 to 7.46+0.06. So the limits are (7.40; 7.52)
Question 1 is about the overlapping response in Group A and Group B. And yes, we have an overlap between 7.35 to 7.39. Among this times both group A and B are in agree with each other within the experimental uncertainty.
Question 2 is now referring to Group A and Group C. And no, there isn't any common time where both groups agree with each other.
