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3 years ago

A CD store sold 3467 CDs in 7 days about the same number of CDs were sold each day how many CDs did the store sell in one day

Mathematics

2 answers:

Mrac [35]3 years ago

8 0

I'm GUESSING about 495 in one day

Novay_Z [31]3 years ago

7 0

About 495 CDs in a single day

3467/7=495+ small decimal

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which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater

Nutka1998 [239]

Answer:

$\frac{\sqrt[3]{16y^4}}{x^2}$

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices $\sqrt[n]{a} = a^{\frac{1}{n}}$

So,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ gives

$\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}$

Also from laws of indices

$(ab)^n = a^nb^n$

So, the above expression can be further simplified to

$\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}$

Multiply the exponents gives

$\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

Substitute $2^5$ for 32

$\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

From laws of indices

$\frac{a^m}{a^n} = a^{m-n}$

This law can be applied to the expression above;

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$ becomes

$2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}$

Solve exponents

$2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}$

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$

From laws of indices,

$a^{-n} = \frac{1}{a^n}$ ; So,

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$ gives

$\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}$

The expression at the numerator can be combined to give

$\frac{(2y)^{\frac{4}{3}}}{x^2}$

Lastly, From laws of indices,

$a^{\frac{m}{n} = \sqrt[n]{a^m}$ ; So,

$\frac{(2y)^{\frac{4}{3}}}{x^2}$ becomes

$\frac{\sqrt[3]{(2y)}^{4}}{x^2}$

$\frac{\sqrt[3]{16y^4}}{x^2}$

Hence,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ is equivalent to $\frac{\sqrt[3]{16y^4}}{x^2}$

8 0

3 years ago

Solve each of the quadratic equations. 3x=0.5x^2 0=5x^2-2x+6

Kipish [7]

Answer:

6x=0.10x< 2

Step-by-step explanation:

8 0

3 years ago

The American Water Works Association reports that the per capita water use in a single-family home is 74 gallons per day. Legacy

Lunna [17]

Answer:

Reject H0 since test statistic <-2.492

Step-by-step explanation:

Given that the American Water Works Association reports that the per capita water use in a single-family home is 74 gallons per day.

n = 25

x bar = 69

s= 8.3

std error = s/sqrt n = $\frac{8.3}{5} \\=1.66$

H0: $\bar x = 74$

Ha: $\bar x$

(Left tailed test at 5% significance level)

a) Reject H0 if t $\leq$ -2.492

b) Test statistic = mean difference/std error

= $\frac{69-74}{1.66} \\=-3.012\\$

=-3.01

df =24

c) Reject H0

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3 years ago

Each child at a birthday party was given $5 to spend at the arcade on games and rides. Each game costs $0.25 and each ride costs

Dmitrij [34]

No it is not possible to play 12 games and go on 6 rides

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3 years ago

Blue paper chains 4 inches long. Red paper chains are 3 inches long. How many are needed to have 10 inches of paper chains?

bixtya [17]

1 blue paper chain and 2 red paper chains

7 0

3 years ago

Read 2 more answers