Can you help me with my math
1 answer:
You might be interested in
<u>Answer:</u>
Below!
<u>Step-by step explanation:</u>
<u>We know that:</u>
- 400 + 850 + m = 1500
<u>Solution of Question A:</u>
<u>Percent of children: Total children/Total attendance</u>
- => 400/1500
- => 4/15
- => 0.27 (Rounded to nearest hundredth)
- => 0.27 x 100
- => 27%
<u>Hence, the percent of children is about 27%.</u>
<u>Solution of Question B:</u>
<u>Percent of women: Total women/Total attendance</u>
- => 850/1500
- => 85/150
- => 17/30
- => 17/30 x 100
- => 17/3 x 10
- => 170/3
- => 56.67%
<u>Hence, the percent of women is 56.67%.</u>
<u>Solution of Question C:</u>
- 400 + 850 + m = 1500
- => 1250 + m = 1500
- => m = 1500 - 1250
- => m = 250
<u>Percent of men: Total men/Total attendance</u>
- => 250/1500
- => 1/6
- => 0.17 (Rounded to nearest hundredth)
- => 0.17 x 100
- => 17%
<u>Hence, the percent of men is about 17%</u>
Hoped this helped.
Answer:
<em>See the Venn diagram attached</em>
<u>Numbers given:</u>
- <em>Total</em>: 100
- Either a cat of a fish: 70
- Cat: 46
- Cat and fish: 16
<u>Neither a cat or a fish:</u> 100 - 70 = 30
<u>Fish:</u> 70 - (46 + 16) = 70 - 62 = 8
<u>Required probabilities are:</u>
- a) P(neither) = 30/100 = 0.3
- b) P(f) = (16 + 8)/100 = 0.24
- c) P(f not c) = 8/100 = 0.08
