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Bad White [126]
3 years ago
8

What is the equation of the asymptote of the function below? f(x)=3^x+7?

Mathematics
2 answers:
postnew [5]3 years ago
8 0
Horizontal asymptote y=7
Umnica [9.8K]3 years ago
3 0

Answer: Horizontal Asymptote: y = 7

Y = 3^x + 7

Step-by-step explanation:

Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is y = 7

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(3/5) / (15/6)<br> _________<br> Show Work
Gala2k [10]
(3/5) : (15/6) ===> (3/5) X (6/15) = 18/75 =6/25
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Please explain how to solve this (<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Ba%5E5%20b%5E3%7D%20" id="TexFormula1" ti
olchik [2.2K]
2 is the base and (\sqrt[4][a^5 b^3]) is the exponent.

the 4 is called an index and it means to fi d the fourth root of the expression under the (\sqrt[][text]) symbol.\\a fourth root is a factor that was multiplied four times. ex: 2*2*2*2=16. the fourth root of 16 is two. \\when you do square roots, you take the number representing the factor out of the radical. anything else that is not a square root stays under. ex: \\([tex]\sqrt[9][text])\\([tex]\sqrt[3*3*3][text]) there is one set of two 3's so\\([tex]3\sqrt[3][text])\\with a fourth root, you look for groups of four. the symbol of that group is placed outside the radical. anything else stays in.\\ ([tex]\sqrt[4][a^5 b^3])

(\sqrt[4][a*a*a*a*a*b*b*b]) there is one group of 4 a's so

(a\sqrt[4][a* b^3])

there really isn't anything else to do to simplify the expression
5 0
2 years ago
HELP !! anyone please i need this done in less than in hour JUST ANSWERS WILL DO
MrRa [10]

Answer:

Step-by-step explanation:

4 0
1 year ago
Need help with this work sheet
Lesechka [4]

Answer:

its alot to explain but i will try to make it as simple as possible

Step-by-step explanation:

your first goal is to make each problem into the form ax^2+bx+c=0

number 1, 2, 7 and 8 is already done for you

now all you have to do is plug in each number in the standard form into the quadtratic formula.

basically at this point you can just use your calculator to do the rest of the work. dont forget parentheses so it doesnt get confused...

or you can perform the algebraic work.. its all just a matter of plugging in the right numbers into the quadratic formula...

cant really do the work for you since im on my phone. but yeah all you need to do step one is transform each problem into ax^2+bx+c=0 form

then step 2, plug in each number in to the quadtratic formula. from there calculate using basic algebraic rules

5 0
3 years ago
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