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Bond [772]
3 years ago
12

A spherical helium balloon has a diameter of 30 cm. How much helium is needed to fill the balloon, in cubic centimeters? Round y

our answer to the nearest centimeter
Mathematics
1 answer:
GaryK [48]3 years ago
3 0
From V= 4/3*pi*r^3 
<span>dV/dt = 4pi(r^2)dr/dt </span>
<span>so when dV/dt=30 and r = 19 </span>
<span>30 = 4pi(361)dr/dt </span>
<span>dr/dt = 30/[4pi(361)] </span>

<span>now in </span>
<span>A = 4pir^2 </span>
<span>dA/dt = 8pi(r)dr/dt </span>
<span>= 8pi(19)*30/[4pi(361)] </span>
<span>= you finish it.</span>
<span>HOPE THIS HELPS.
</span>
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In a basketball game, a regular basket was worth 2 points and a long-distance basket was worth 3 points. If there were 45 basket
-BARSIC- [3]

Answer:

B. r + l = 45; 2r + 3l = 96

39 regular; 6 long-distance

Step-by-step explanation:

There were 45 baskets, so

(1) r + l = 45

There were 96 points in the game, so

(2) 2r + 3l = 96

Solve equation (1) for l

                    l = 45 – r     Substitute the value for l in Equation (2)

2r + 3(45 – r) = 96      Remove parentheses

 2r + 135 - 3r = 96      Combine like terms

         -r + 135 = 96      Subtract 135 from each side

                  -r = -39      Multiply each side by -1

                  r = 39      Substitute the value of r in Equation (1)

           39 + l = 45        Subtract 39 from each side

                   l = 6

===============

Check:

(1) 39 + 6 = 45

         45 = 45

(2) 2×39 + 3×6 = 96

           78 + 18 = 96

                   96 = 96


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3 years ago
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Answer:

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Step-by-step explanation:

hope it helps :3

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