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Kipish [7]
3 years ago
10

Regina drew a triangle with vertices at ( 1 , 2 ) , ( 3 , 3 ) , and ( 4 , 1 ) . She slides the triangle 2 units down to create a

n image. What are the vertices of the image? A. ( 1 , 0 ) , ( 3 , 1 ) , and ( 4 , − 1 )
B. ( 1 , 4 ) , ( 3 , 5 ) , and ( 4 , 3 )
C. ( − 1 , 2 ) , ( 1 , 3 ) , and ( 2 , 1 )
D. ( 3 , 2 ) , ( 5 , 3 ) , and ( 6 , 1 )
Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
6 0

Answer:  The correct option is

(A) (1, 0), (3, 1) and (4, -1).

Step-by-step explanation:  Given that Regina drew a triangle with vertices at (1 , 2), (3 , 3) and (4 , 1). She slides the triangle 2 units down to create an image.

We are to find the vertices of the image.

We know that

if a point (x, y) is translate 2 units down, its co-ordinates changes as follows :

(x,y)~~~\Rightarrow~~~(x,y-2).

Therefore, the vertices of the image of the given triangle are

(1, 2)  ⇒  (1, 2-2) = (1, 0),

(3, 3)  ⇒  (3, 3-2) = (3, 1)

and

(4, 1)  ⇒  (4, 1-2) = (4, -1).

Thus, the required co-ordinates of the image are (1, 0), (3, 1) and (4, -1).

Option (A) is CORRECT.

Katen [24]3 years ago
5 0

Answer:

Its C

Step-by-step explanation:

Okay so you are basically just moving the triangle down two Right? So I believe you are only going to be changing your x axis which is the first out of the two numbers. So your gonna think of it as subtracting 2 from the x axis numbers. Examples, (1,2) you would change that to (-1,2). Or (3,3) that would change to (1,3). Or (4,1) that would change to (2,1). If you do not understand than think of it as money. like if you have 1 dollar but owed two dollars than you would have to owe 1 dollar and Etc

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Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui
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<h3>The dimensions of the given rectangular box are:</h3><h3>L  =   15.874 cm  , B  =  15.874 cm   , H = 7.8937 cm</h3>

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Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box  

= Area of the base +  4 x ( Area of the adjacent faces)

=  S x S  +  4 ( S x H)   = S² +  4 SH   ..... (1)

Also, Area of the box  = S x S x H  =  S²H

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\implies H = \frac{2000}{S^2}

Substituting the value of H in (1), we get:

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Hence, the dimensions of the given rectangular box are:

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B  = 15.874 cm

H = 7.8937 cm

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