Regina drew a triangle with vertices at ( 1 , 2 ) , ( 3 , 3 ) , and ( 4 , 1 ) . She slides the triangle 2 units down to create a
2 answers:
Answer: The correct option is
(A) (1, 0), (3, 1) and (4, -1).
Step-by-step explanation: Given that Regina drew a triangle with vertices at (1 , 2), (3 , 3) and (4 , 1). She slides the triangle 2 units down to create an image.
We are to find the vertices of the image.
We know that
if a point (x, y) is translate 2 units down, its co-ordinates changes as follows :
Therefore, the vertices of the image of the given triangle are
(1, 2) ⇒ (1, 2-2) = (1, 0),
(3, 3) ⇒ (3, 3-2) = (3, 1)
and
(4, 1) ⇒ (4, 1-2) = (4, -1).
Thus, the required co-ordinates of the image are (1, 0), (3, 1) and (4, -1).
Option (A) is CORRECT.
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Answer:
a.) f'(x) = 2x - 2
b.) horizontal tangent line at (1, 0)
c.) view image
d.) the point given, (-1, -1/2), isn't even located on the graph of f(x). Either there is a typo or the question is poorly stated.
Step-by-step explanation:
a.) You should know how to do derivative already
b.) Horizontal tangent line just mean that the slope is zero. Since a derivative is a slope, just find when the derivative is equal to 0.
c.) The function f(x) looks like a U. The only spot that has a zero slope is at the bottom of the U when the slope changes from negative to positive. Since my horizontal tangent line(where the slope is 0) is located at point (1,0), that must be where the bottom of the graph is,
d.) Poorly stated question. The point given isn't even located on the graph.
