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leva [86]
4 years ago
9

Kinetic molecular theory makes several assumption about

Chemistry
1 answer:
WITCHER [35]4 years ago
4 0

Answer:

Explanation:

The KM Theory is the 'micro' molecular description of the behavior of matter. That is, the theory takes into account particle-particle interactions. This is contrast with the 'macro' molecular description of matter that is based upon empirical relationships without taking into account particle - particle interactions.

For example, Charles Law defines the relationship of gas volume as a function of temperature as being direct. That is, an increase in temperature results in an increase in volume of gas. No mention is made of the fact that the increasing temperature is increasing the kinetic energy content of the particles causing an increase in velocity of the particles.

However, application of the principles of the KM Theory takes into account the relationship between kinetic energy and particle velocity in terms of increasing temperature and transfer of energy to specific quantities of matter. Such results are based upon probability concepts that 4 primary reaction factors must come together simultaneously to effect a chemical reaction. These are ...

1. reactive <u>concentration</u> of reactants => C

2. effective collisions occurring (orientation of particles on collisions) => E

3. the interaction of reactive structures by nature => N

4. temperature - energy conditions initiate reaction (activation energy point) => T

These are assumptions are 'reaction factors' (=> C.E.N.T for memory purposes) that must come together simultaneously to effect a reaction. The greatest probability of this occurring is at the temperature condition called the 'Activation Energy'. The relationship that defines this probability is called the Arrhenius Equation k = Ae^-ΔEₐ/RT where k is the kinetic rate constant, A is a proportionality constant, ΔEₐ the Activation Energy and T the Kelvin Temperature.          

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A beaker and a microscope
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Using the information in the table, calculate the number of moles in a \pu{7.89 kg}7.89 kg7, point, 89, space, k, g sample of as
Karolina [17]

We have to find the number of moles in a 7.89 kg sample of aspirin.

The formula of aspirin is: C₉H₈O₄

We are given the molar mass of C, H and O:

H: 1.008 g/mol C: 12.01 g/mol O: 16.00 g/mol

Since one molecule of aspirin has 9 atoms of C, 8 atoms of H and 4 atoms of O, and using the molar masses given, we can calculate the molar mass of aspirin:

molar mass of aspirin = 9 * 12.01 g/mol + 8 * 1.008 g/mol + 4 * 16.00 g/mol

molar mass of aspirin = 180.154 g/mol

Before we find the number of moles we can convert 7.89 kg to g. Since we know that there are 1000 g in 1 kg, we can convert it like this:

1000 g = 1 kg

mass of sample = 7.89 kg * 1000 g/1 kg

mass of sample = 7890 g

Finally, we can find the number of moles in the sample using the molar mass.

number of moles = 7890 g * 1 mol/180.154 g

number of moles = 43.795 moles

Answer: The number of moles in the sample is 43.8 moles (using 3 SF)

7 0
1 year ago
What happens to the temperature of the liquid in a cup of water as some of the water evaporates?
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C. The temperature decreases because the most energetic molecules escape.


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PLEASE HURRY AND CHECK IMMAGE. Predict the shape of the molecule.
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Answer:

A. bent

Explanation:

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3 years ago
If a gas has a volume of 1000 ML at a temperature of 23°C and a pressure of 100 mmhg, what is it’s volume under standard conditi
Colt1911 [192]

Answer:

119.7 mL.

Explanation:

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<em>PV = nRT.</em>

where, P is the pressure of the gas.

V is the volume of the container.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas (K).

  • For the same no. of moles of the gas at two different (P, V, and T):

<em>P₁V₁/T₁ = P₂V₂/T₂.</em>

  • P₁ = 100.0 mmHg, V₁ = 1000.0 mL, T₁ = 23°C + 273 = 296 K.
  • P₂ = 1.0 atm = 760.0 mmHg (standard P), V₂ = ??? mL, T₂ = 0.0°C + 273 = 273.0 K (standard T).

<em>∴ V₂ = (P₁V₁T₂)/(T₁P₂) </em>= (100.0 mmHg)(1000.0 mL)(273.0 K)/(296 K)(760.0 mmHg) =  121.4 <em>mL.</em>

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