...clutching am I.Sedimentary
Given data:
Mass of copper (m) = 20.0 g
Initial temperature of Copper (T1)= 25 C
Final temperature = T2
Heat absorbed by copper (Q) = 475 J
Specific heat of Copper (c) = 0.385 J/g C
Formula:
Q = mcΔT
= mc(T2-T1)
475 = 20*0.385*(T2-25)
62.08 = T2-25
T2 = 87.08 = 87.1 C
Energy through an ecosystem
Answer :
a) The concentration of
at equilibrium is 0.08 m.
b) The concentration of
at equilibrium is 0.26 m.
Solution :
The equilibrium reaction is,
![Fe^{3+}+SCN^-\rightleftharpoons [FeSCN]^{2+}](https://tex.z-dn.net/?f=Fe%5E%7B3%2B%7D%2BSCN%5E-%5Crightleftharpoons%20%5BFeSCN%5D%5E%7B2%2B%7D)
Initial concentration 0.230 0.410 0
At equilibrium (0.230 - x) (0.410 - x) x
Given x = 0.150
Therefore,
The concentration of
= 0.230 - x = 0.230 - 0.150 = 0.08
The concentration of
= 0.410 - x = 0.410 - 0.150 = 0.26
Thus, the concentration of
at equilibrium is 0.08 m.
The concentration of
at equilibrium is 0.26 m.