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2 years ago

A student repeats a reaction several times to test the effects of various

Chemistry

2 answers:

Nookie1986 [14]2 years ago

8 0

Answer:

C) Decreasing the concentration would decrease the reaction rate.

Explanation:

A.P.E.X

motikmotik2 years ago

7 0

Decreasing the concentration would decrease the reaction rate (option c)

The aforementioned statement is due to the fact that when a substance's concentration is high, it will quickly perform the chemical reaction as there are more particles reacting with one another. Conversely, if there is less of a concentration, then the reaction rate would decrease as there are little particles reacting with one another.

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3 years ago

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Natural gas is almost entirely methane. A container with a volume of 2.65L holds 0.120mol of methane. What will the volume be if

mrs_skeptik [129]

The final volume of the methane gas in the container is 6.67 L.

The given parameters;

initial volume of gas in the container, V₁ = 2.65 L
initial number of moles of gas, n₁ = 0.12 mol
additional concentration, n = 0.182 mol

The total number of moles of gas in the container is calculated as follows;

$n_t = 0.12 + 0.182 = 0.302 \ mol$

The final volume of gas in the container is calculated as follows;

$PV = nRT\\\\\frac{V}{n} = \frac{RT}{P} \\\\\frac{V_1}{n_1} = \frac{V_2}{n_2} \\\\V_2 = \frac{V_1 n_2}{n_1} \\\\V_2 = \frac{2.65 \times 0.302}{0.12} \\\\V_2 = 6.67 \ L$

Thus, the final volume of the methane gas in the container is 6.67 L.

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2 years ago