Answer:
Propenyl-benzene
Explanation:
Hello,
Elimination reaction of solid (1-chloropropyl)-benzene due to the heat in presence of ethanol turns out based on the attached picture in which both the chlorine a the hydrogen in the second carbon go out and subsequently get together to form propenyl-benzene and hydrochloric acid.
Best regards.
3k= 3 Potassium atoms
2S= 2 sulfur atoms
2O4= 8 oxygen atoms
The numbers in front of atoms are like coefficients(i.e. 2x or 3y). You should have 13 atoms in total.
Answer: C₃H₂
Explanation:
1) Since you are told naphthelene is a hydrocarbon, you know that its chemical formula only has atoms of C and H.
2) Since combustion adds O but not C nor H, you know that all the C and H present in the products come from the naphthelene sample.
3) Calculate the amount of C in 13.20 grams of CO₂:
Use atomic masses:
C: 12.01 g/mol
O: 16.00 g/mol
⇒ molar mass of CO₂ = 12.01 g/mol + 2×16.01 g/mol = 44.01 g/mol
Proportion of C in 13.20 g of CO₂
12.01 g C / 44.01 g CO₂ = x / 13.20 g CO₂ ⇒
x = 13.20 g CO₂ × 12.01 g C / 44.01 g CO₂ = 3.602 g C
3) Calculate the mass of H in 1.80 g of H₂O
Atomic masses:
H: 1.01 g/mol
O: 16.0 g/mol
Molar mass H₂O = 18.02 g/mol
Proportion of H in 1.80 g H₂O
2.02 g H / 18.02 g H₂O = x / 1.80 g H₂O
x = 1.80 gH₂O × 2.02 g H / 18.02 gH₂O = 0.202 g H.
4) Calculate the number of moles of C and H in the masses calculated above
Number of moles of C = 3.602 g C / 12.01 g/mol = 0.3 mol
Number of moles of H = 0.202 g / 1.01 g/mol = 0.2 mol
5) Divide both amounts by the smallest one to calculate the proportion in moles:
C: 0.3 / 0.2 = 1.5 mol
H = 0.2 / 0.2 = 1 mol
Multiply by 2 to obtain integers:
C: 3
H: 2
6) Then the proportion leads to the empirical formula C₃H₂
The answer is A.
During any chemical change the total mass doesn’t changes. Whatever the total mass of starting materials was present the same mass of ending products is present in a chemical reaction.
Your weight would be less but your mass would remain the same.
