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Arturiano [62]
3 years ago
15

A jar containing only nickels (n) and dimes (d) contains a total of 60 coins. the value of all the coins in the jar is $4.45. wr

ite and solve a system of equations to find the amount of nickels and dimes that are in the jar.
Mathematics
1 answer:
natka813 [3]3 years ago
5 0
<span>D=1.45/.05
D=29 DIMES.
60-29=31 NICKELS.
PROOF:
.05*31+.10*29=4.45
1.55+2.90=4.45
4.45=4.45 </span>
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Answer:

a) p=0.021

b) p=0.029

c) Exactly one audit: P=0.0965

More than one audit: P=0.0042

Step-by-step explanation:

a) If the income is less than $100,000, there is a probability of 21 in 1,000 of being audited. This is:

p_1=\dfrac{21}{1,000}=0.021

If the income is equal or more than $100,000, there is a probability of 29 in 1,000 of being audited. This is:

p_2=\dfrac{29}{1,000}=0.029

b) If we have 5 taxpayers with incomes under $100,000, and we want to know the probability that exactly one will be audited, we can model this a binomial randome variable, with p=0.021 and n=5:

P(x=1) = \dbinom{5}{1} p^{1}q^{4}=5*0.021*0.9186=0.0965\\\\

There is a probability of 0.0965 that exactly one out of a sample of five taxpayers with incomes under $100,000 will be audited.

To calculate the probability that more than one will be audited, we use the same distribution:

P(x>1)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0) = \dbinom{5}{0} p^{0}q^{5}=1*1*0.8993=0.8993\\\\\\P(x=1) = \dbinom{5}{1} p^{1}q^{4}=5*0.021*0.9186=0.0965\\\\\\P(x>1)=1-[P(x=0)+P(x=1)]\\\\P(x>1)=1-(0.8993+0.0965)\\\\P(x>1)=1-0.9958\\\\P(x>1)=0.0042

There is a probability of 0.0042 that more than one out of a sample of five taxpayers with incomes under $100,000 will be audited.

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The population of a city increases by 10,000 per year. The starting population is 800,000.
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