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3 years ago

2 ratios equivalent to 8\3

1 answer:

3 0

Some equivalent fractions of 8/3 are:
8/3 = 16/6 = 24/9 = 32/12 = 40/15 = 48/18 = 56/21 = 64/24 = 72/27 = 80/30 = 88/33 = 96/36 = 104/39 = 112/42 = 120/45 = 128/48 = 136/51 = 144/54 = 152/57 = 160/60

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First-order linear differential equations

kkurt [141]

Answer:

$(1)\ logy\ =\ -sint\ +\ c$

$(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Step-by-step explanation:

1. Given differential equation is

$\dfrac{dy}{dt}+ycost = 0$

$=>\ \dfrac{dy}{dt}\ =\ -ycost$

$=>\ \dfrac{dy}{y}\ =\ -cost dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}$

$=>\ logy\ =\ -sint\ +\ c$

Hence, the solution of given differential equation can be given by

$logy\ =\ -sint\ +\ c.$

2. Given differential equation,

$\dfrac{dy}{dt}\ -\ 2ty\ =\ t$

$=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty$

$=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})$

$=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}$

$=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c$

$=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Hence, the solution of given differential equation is

$log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

8 0

4 years ago

En 4 días un hombre recorrió 120 km. Si cada día avanzó 1/3 de lo que anduvo el día anterior, en el segundo día recorrió.

ioda

Answer:

36 Km

Step-by-step explanation:

Por favor, encontrar el archivo adjunto

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3 years ago

Complete the equation that represents the line.<br> Write it in slope-intercept form.

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Y=2x+2 the equation that represent the line

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3 years ago

Question 5 - a , b , c , d ??

wel

A) 110/21 = 5 5/21
B) 10
C) 21/4 = 5 1/4
D) 16/5 = 3 1/5

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3 years ago

Compared to women in the North, women in the South during the Civil War often

Novay_Z [31]

Answer:D

Step-by-step explanation:

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3 years ago

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