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Kruka [31]
3 years ago
6

Wich of the following functions maps 3 to -5?

Mathematics
1 answer:
kolezko [41]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Consider all options and find f(3):

A.

Then

Not -5, so this option is false.

B.

Then

This option is true.

C.

Then

Not -5, so this option is false.

D.

Then

Not -5, so this option is false.

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Answer:

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Given a=-3,b=4 and c=-5, evaluate a-b-c<br><br> A.-12<br> B.-6<br> C-2
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Answer:

C

Step-by-step explanation:

a-b-c

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A present is shaped like a
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What value of x is in the solution set of –5x – 15 &gt; 10 + 20x?
Blizzard [7]
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7 0
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Read 2 more answers
PLEASE HELP! URGENT! Exponential function f is being represented by the table (photo attached) the function “g” is an exponentia
Y_Kistochka [10]

Answer:

C) Both functions are decreasing and both are positive on the interval (0;2)

Step-by-step explanation:

As known the exponent function has no minimum and has no maximum.

Otherwise exponent function can be only or increasing or decreasing for all x.

That means that in case y(x2)>y(x1) and  if x2>x1-  function is increasing.

That means that in case y(x2)<y(x1) and  if x2>x1-  function is decreasing.  

Lets check what is going on with the function f(x)

If x1=0        f(x1)=24

If x2=2        f(x2)=0

So    x2>x1 however f(x2)<f(x1)=> function is decreasing

Similarly g(x)

If x1=0   g(x1)=15

If x2=2   g(x2)=0

So x2>x1 however g(x2)<g(x1) => function is decreasing

So bothfunctions are decreasing.

Because f(x) is decreasing the function meaning with argument x1=0 has max in the interval x∈(0;2) And function meaning has the minimum if argument x2=2.   So the function F(x) in interval (0;2) is changing from 24 to 0 => is positive on the interval (0,2)

The same is with g(x) .  g(x) gonna be positive on the interval (0;2)

6 0
3 years ago
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