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2 years ago

Wich of the following functions maps 3 to -5?

Mathematics

1 answer:

kolezko [41]2 years ago

5 0

Answer:

Step-by-step explanation:

Consider all options and find f(3):

Then

Not -5, so this option is false.

Then

This option is true.

Then

Not -5, so this option is false.

Then

Not -5, so this option is false.

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Find the value of x in the triangle below

Tom [10]

Answer:

6.76

Step-by-step explanation:

applying pythogorem theorem

a^2+b^2=c^2

5^2+b^2=13^2

25+b^2=169

b^2=169/25

b^2=6.76^2

b=6.76

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2 years ago

Cuanto es menos 7 mas 2

irina [24]

Answer:

the answer is -5. you could really just use a calculator this is pretty basic math.

Step-by-step explanation:

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2 years ago

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What is the radius of a circle whose equation is x² + y² + 8x – 6y + 21 = 0? <br><br> __?__ units

BlackZzzverrR [31]

(x+4)^2 + (y-3)^2 = 4

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3 years ago

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Find the Laplace transformation of each of the following functions. In each case, specify the values of s for which the integral

MAVERICK [17]

Answer:

a. $\frac {2} {s-1}$ converges to s> 1.

b. $\frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $- \frac {2}{s + 3}$ converges to s> - 3.

d. $\frac {s}{s^2 + 25}$ converges to s> 0.

e. $\frac {10} {s^2 + 1}$ converges even s> 0.

f. $\frac {12}{s^2 + 4}$ converges to s> 0.

g. $-\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $\frac {1} {s ^ 2 + 4}$ converges to s> 0.

Step-by-step explanation:

a. $L \left\{2e^t \right\} = 2L \left\{e^t \right\} = 2 \cdot \frac {1} {s-1} = \frac {2} {s-1}$ converges to s> 1.

b. $L \left\{3e^{5t-3} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = \frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $L \left\{-2e^{-3t} \right\} = -2L \left\{e^{-3t} \right\} = - \frac {2}{s + 3}$ converges to s> - 3.

d. $L \left\{\cos\left (5t \right)\right\} = \frac {s}{s^2 + 25}$ converges to s> 0.

e. $L \left\{10 \sin\left(t\right)\right\} = 10L\left\{\sin\left(t\right)\right\} = \frac {10} {s^2 + 1}$ converges even s> 0.

f. $L \left\{6\sin \left(2t \right) \right\} = 6L\left\{\sin\left (2t\right)\right\} = \frac {12}{s^2 + 4}$ converges to s> 0.

g. $L \left\{-5\cos\left(2t + 1\right) \right\} = -5L\left\{\cos\left(2t + 1 \right)\right\} = -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $L\left\{\sin \left(t\right)\cos \left(t\right)\right\} = L\left\{\sin\left(2t\right)\frac{1}{2}\right\} =\frac{1}{2}\cdot \frac{2}{s^2+4} = \frac {1} {s ^ 2 + 4}$ converges to s> 0.

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3 years ago

(2*1) +(6*1/1,000) write in standard form

Pani-rosa [81]

Multiply and add it up and you got ur answer

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2 years ago