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2 years ago

Answer plsssssssssssssssss

Mathematics

2 answers:

matrenka [14]2 years ago

6 0

Answer:

i think the second answer

Step-by-step explanation:

a_sh-v [17]2 years ago

3 0

Answer: y=2/5x-3

Step-by-step explanation:

Since the b value in y=mx+b is the y-intercept we can rule out the 2 answers on the right as they have a y-intercept of -1

Now, let's test the point on one of the functions, take y=-4/5x-3 and substitute 5 for x and -1 for y

-1=4/5(5)-3

-1=4-3

-1=1

The left side does not equal the right side meaning the point does not pass through the function. Therefore, y=2/5x-3 is the correct answer

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f the points (-4, 1) and (2, 1) are the endpoints of a diameter of a circle, where is the center? A) (-7, 1) B) (-1, 1) C) (1, -

Ulleksa [173]

Answer:

Step-by-step explanation:

The centre is at the midpoint of the endpoints of the diameter.

Using the midpoint formula, then

centre = ( $\frac{-4+2}{2}$ , $\frac{1+1}{2}$ ) = (- 1, 1 ) → B

4 0

2 years ago

8. What expression is equivalent to 3y – 21?

disa [49]

3(y-7)

use distributive property

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2 years ago

Tank 1 initially contains 50 gals of water with 10 oz of salt in it, while tank 2 initially contains 20 gals of water with 15 oz

Naddik [55]

$\dfrac{\mathrm dx_1}{\mathrm dt}=\dfrac{2\text{ oz}}{1\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}-\dfrac{x_1(t)\text{ oz}}{50\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}$
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$\implies\begin{cases}\dfrac{\mathrm dx_1}{\mathrm dt}=10-\dfrac1{10}x_1\\\\\dfrac{\mathrm dx_2}{\mathrm dt}=\dfrac1{10}x_1-\dfrac14x_2\\\\x_1(0)=10\\\\x_2(0)=15\end{cases}$

6 0

2 years ago

The family of functions y = ce^{-2x} + e^{-x} is solution of the equation y' + 2y = e^{-x}. Find the constant c which defines th

Rufina [12.5K]

Answer:

$c = 1190.2$

Step-by-step explanation:

We have the following solution:

$y(x) = ce^{-2x} + e^{-x}$

We want to find the value of x that satisfies the following condition:

y(3) = 3.

This means that when x = 3, y = 3. So

$y(x) = ce^{-2x} + e^{-x}$

$y(3) = ce^{-2*3} + e^{-3}$

$3 = ce^{-6} + e^{-3}$

$3 = ce^{-6} + 0.0498$

$ce^{-6} = 2.9502$

$c = \frac{2.9502}{e^{-6}}$

$c = 1190.2$

4 0

2 years ago

What expressions are equivalent to q+p+q+p+q

Kipish [7]

You can resolve all of them.
so the first one would be 3q+2p
that second 2p+3q
the third 2p+2q+q which equals 2p+3q

they all end up as the same thing so both are equivalent

6 0

3 years ago