3 years ago

What is the radius of the circle with this equation of (x-5)2+(y+7)2=8

Mathematics

1 answer:

AysviL [449]3 years ago

3 0

Answer:

2√2

Step-by-step explanation:

compare this equation with the standard equation of a circle centered at (h, k) with radius r:

(x - h)^2 + (y - k)^2 = r^2

(x - 5)^2 + (y + 7)^2=8

Clearly, r^2 = (radius)^2 = 8, and so the radius, r, is √8, or 2√2

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