Question

A 15 A current is directed along the positive x-axis and perpendicular to a uniform magnetic field. The conductor experiences a magnetic force per unit length of 0.20 N/m in the negative y direction. Calculate the magnitude of the magnetic field in the region through which the current passes. Answer in units of T.

Answer 1

Answer:

The magnitude of magnetic field in the region through the current passes is 0.0133 T

Explanation:

Given:

Current $I = 15$ A

Force per unit length $\frac{F}{l} = 0.20 \frac{N}{m}$

The magnetic force on current carrying conductor is given by,

   $F = IlB$

For finding the magnetic field,

   $B = \frac{F}{Il}$

   $B = \frac{0.20}{15}$

   $B = 0.0133$ T

Therefore, the magnitude of magnetic field in the region through the current passes is 0.0133 T