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masya89 [10]
3 years ago
8

I NEED HELP SOLVING THIS!!!!!!!!!!!!

Physics
1 answer:
Neko [114]3 years ago
7 0

Answer:

Yes

Explanation:

The given parameters are;

The speed with which the fastball is hit, u = 49.1 m/s (109.9 mph)

The angle in which the fastball is hit, θ = 22°

The distance of the field = 96 m (315 ft)

The range of the projectile motion of the fastball is given by the following formula

Range = \dfrac{u^2 \times sin(2\cdot \theta)}{g}

Where;

g = The acceleration due to gravity = 9.81 m/s², we have;

Range = \dfrac{49.1^2 \times sin(2\times22^{\circ})}{9.81} \approx 170.71 \ m

Yes, given that the ball's range is larger than the extent of the field, the batter is able to safely reach home.

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Answer:

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4) v = 17.15 [m/s]

Explanation:

3) In order to solve this problem, we must use the principle of energy conservation. That is, the energy will be transformed from potential energy to kinetic energy. We can calculate the potential energy with the mass and height data, as shown below.

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