A horizontal spring with spring constant 85 N/m extends outward from a wall just above floor level. A 5.5 kg box sliding across
a frictionless floor hits the end of the spring and compresses it 6.5 cm before the spring expands and shoots the box back out. How fast was the box going when it hit the spring
1 answer:
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Answer:
t = 5.48 × 10⁻³ s
Explanation:
Given:
ΔV = ΔVmax × sin(2πft)
frequency, f = 16.9Hz
thus,
ΔV = ΔVmax × sin(2π×16.9×ft)
Now,
Let 'R' be the resistance
Also according to the ohms law
i = V/R
where,
i = current
V = voltage
hence,
also, given at time 't' the current in the circuit is 55.0% of the peak current
thus
thus,
or
or
or
t = 5.48 × 10⁻³ s (Answer)