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4vir4ik [10]
2 years ago
6

Which cannot be the angle measurements of triangle ABC? a. m b. m c. m d. m

Mathematics
2 answers:
densk [106]2 years ago
6 0
Ummmmm it has to bee m. If that all you have us to pick
jarptica [38.1K]2 years ago
5 0

Answer:

Measure of angle A = 61 degrees, measure of angle B = 57 degrees, measure of angle C = 61 degrees  or D

Step-by-step explanation:

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Ram wants to work to preserve marine habitats. Which field of study would be most useful to him
Nataliya [291]
<span>Oceanography the others are other studies 

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8 0
3 years ago
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Solve for y -9x+y=6. how can you get y .
Roman55 [17]
Pretty much you’re going to need to subtract the -9x to get it on the other side, so that you get y= 9x+6

3 0
2 years ago
What fraction is equivalent to 30/360?
Firdavs [7]

Answer:

1/12

Step-by-step explanation:

Given that

30/360 to lowest fraction equivalent

Now, we can write 30 as 3×10

Also, we can write 360 as 36×10

Then, we have

(3×10)/(36×10)

Then, 10 cancel 10, we are left with

3/36

Also we can write 36 as 12×3

Then, we have

3/(12×3)

Also, 3 cancel 3, we are left with

1/12

Then the lowest fraction is 1 / 12

1/12

4 0
2 years ago
Read 2 more answers
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos &#10;y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
Need help with school
zepelin [54]

Answer:

x=6°

Step-by-step explanation:

The value of x is 6°.

5 0
2 years ago
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