Hello :
<span>3y = x + 6 ...(1)
y – x = 3...(2)
by (2) : y = x+3...(*)
subsct in (1) :
3(x+3) = x+6
3x-x= -9+6
2x= -3
x=-3/2
subsct in (*) : y =-3/2 +3 =3/2</span>
Answer:
eight thousand four hundred nine and eight hundredths
Step-by-step explanation:
Answer:
$0.50 for each DVD you reant
Step-by-step explanation:
Answer: -1.8m3n2
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that angle A is in IV quadrant
So A/2 would be in II quadrant.
sin A = -1/3
cos A = 
(cos A is positive since in IV quadrant)
Using this we can find cos A/2
