All categories

3 years ago

Determine the intercepts of the line. 7x-5=4y-6/7x−5=4y−6

Mathematics

2 answers:

DIA [1.3K]3 years ago

5 0

I hope this helps. i didnt get what / meant... did you mean divide?

Whitepunk [10]3 years ago

5 0

Answer:

x.(-1/7,0)

y.(0,1/4)

Step-by-step explanation:

You might be interested in

Which graph represents viable values for y = 5.5x, where x is the number of cans of tomato paste and y is the total weight of th

Brilliant_brown [7]

Answer:

On a coordinate plane, x-axis is numbered negative 5 to positive 5 in increments of 1, and the y-axis is numbered negative 27.5 to 27.5 in increments of 5.5. Solid circles appear at points (0, 0), (1, 5.5), (2, 11), (3, 16.5), (4, 22), (5, 27.5)

Step-by-step explanation:

The first graph is not correct because you cannot sell or buy, for example 1.1, cans of tomato.

The second graph is correct because x is discrete variable, that is, it only take values like 1, 2, 3, etc.

The third and fourth graphs are not correct because you cannot sell or buy negative cans of tomatoes.

6 0

3 years ago

Read 2 more answers

Someone please help me I’m so confused!!!

QveST [7]

Answer:

number one. 186 $in^{2}$ number two. 36 $cm^{2}$

Step-by-step explanation:

FOR NUMBER ONE:

the area of a trapezoid formula is $\frac{a+b}{2} h$ where a and b are the bases and h is the height. so we have to add in the numbers into the formula

$\frac{12+15}{2} * 6\\$ = 81

and the paralellogram formula is b×h. where b is the base and h is height

15 × 7 = 105

so the area of the figure is 81 + 105 is 186 in^2

FOR NUMBER TWO:

the area of the square formula is $s^{2}$ . where s is the side

4^2 = 16

and for the paralellogram is b × h

4 × 5 = 20

so the area of the figure is 16 +20 = 36 in^2

hope this helps! ;)

5 0

3 years ago

Mr Thompson please help with my new HW

sesenic [268]

Answers:

C) x = plus/minus 11
B) No real solutions
C) Two solutions
A) One solution
The value  18  goes in the first blank. The value  17  goes in the second blank.

========================================================

Explanations:

Note how (11)^2 = (11)*(11) = 121 and also (-11)^2 = (-11)*(-11) = 121. The two negatives multiply to a positive. So that's why the solution is x = plus/minus 11. The plus minus breaks down into the two equations x = 11 or x = -11.
There are no real solutions here because the left hand side can never be negative, no matter what real number you pick for x. As mentioned in problem 1, squaring -11 leads to a positive number 121. The same idea applies here as well.
The two solutions are x = 0 and x = -2. We set each factor equal to zero through the zero product property. Then we solve each equation for x. The x+2 = 0 leads to x = -2.
We use the zero product property here as well. We have a repeated factor, so we're only solving one equation and that is x-3 = 0 which leads to x = 3. The only root is x = 3.
Apply the FOIL rule on (x+1)(x+17) to end up with x^2+17x+1x+17 which simplifies fully to x^2+18x+17. The middle x coefficient is 18, while the constant term is 17.

3 0

3 years ago

Can someone please help

jolli1 [7]

Powers shared by the state and federal government are known as concurrent powers.

4 0

3 years ago

Use the discriminant to describe the roots of each equation. Then select the best description. 2 = x2 + 5x. A) Double root B) Re

fredd [130]

$\bf 2=x^2+5x\implies 0=x^2+5x-2\\\\\\\qquad \qquad \qquad \textit{discriminant of a quadratic}\\\\\\0=\stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+5}x\stackrel{\stackrel{c}{\downarrow }}{-2}~~~~~~~~\stackrel{discriminant}{b^2-4ac}=\begin{cases}0&\textit{one solution}\\positive&\textit{two solutions}\\negative&\textit{no solution}\end{cases}\\\\\\(5)^2-4(1)(-2)\implies 25+8\implies 33$

so we have a 33, namely two real solutions for that quadratic.

usually that number goes into a √, if you have covered the quadratic formula, you'd see it there, namely that'd be equivalent to √(33), now 33 is a prime number, and √(33) is yields an irrational value, specifically because a prime number is indivisible other than by itself or 1.

so 33 can only afford us two real irrational roots.

3 0

3 years ago