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Setler [38]
3 years ago
7

Solve the inequality: -1/4(x^2-4x+3)>0

Mathematics
1 answer:
Montano1993 [528]3 years ago
5 0
Ok so assume that if you have
xy=0 then x and y=0
-1/4(x^2-4x+3)>0
multiply both sides by -4 to clear fraction (-4/-4=1)
flip sign
x^2-4x+3<0
factor
(x-3)(x-1)<0

we know that (+) times (-)=(-) and 
(-) times (-)=(+) so we don't want them to be both negative, we want different sign
we cannnot have 3 since it would be (0)(2)<0 which is false
we cannot have 1 either since (-2)(0)<0 is also false
lets see if the solution is in betwen 3 and 1 or outside of 3 and 1
ltry 2
2^3-4(2)+3<0
8-8+3<0
3<0
false
therefor it is outside ie
x>3 and x<1
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Simplify the expression. 6p5
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3 years ago
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2,−3) B(4,−3) C(4,5) D(2,5
AveGali [126]

Answer:

21 unit square

Step-by-step explanation:

First you want to find the length and width of the rectangle using the distance formula:

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AB=√(6-3)²+ (-2 - -2)²

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BC=√0 + 7²

BC=√49

BC=7

We can find the area by multiplying these two distances together:

A=(3)(7)

A=21 units square.

Hope it helped...... And plz mark BRAINLIEST

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7 0
3 years ago
H(n) = n^3 - 2; Find h(3)
Snezhnost [94]

Answer:

25

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4 0
2 years ago
How to find the area and perimeter of irregular rectangles
LenaWriter [7]
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4 0
3 years ago
<img src="https://tex.z-dn.net/?f=n%20%2B%207%20%3D%2013" id="TexFormula1" title="n + 7 = 13" alt="n + 7 = 13" align="absmiddle"
torisob [31]

n+7=13

Subtract the 7 and eliminate the 7 then subtract from 13 on the other side.

n=6

8 0
3 years ago
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