Ok so assume that if you have xy=0 then x and y=0 -1/4(x^2-4x+3)>0 multiply both sides by -4 to clear fraction (-4/-4=1) flip sign x^2-4x+3<0 factor (x-3)(x-1)<0
we know that (+) times (-)=(-) and (-) times (-)=(+) so we don't want them to be both negative, we want different sign we cannnot have 3 since it would be (0)(2)<0 which is false we cannot have 1 either since (-2)(0)<0 is also false lets see if the solution is in betwen 3 and 1 or outside of 3 and 1 ltry 2 2^3-4(2)+3<0 8-8+3<0 3<0 false therefor it is outside ie x>3 and x<1
